10 more than twice gorans age

A healthcare provider monitors the number of CAT scans performed each month in each of its clinics. The most recent year of data

Rasek [7]

Answer: a. 1.981 < μ < 2.18

b. Yes.

Step-by-step explanation:

A. For this sample, we will use t-distribution because we're estimating the standard deviation, i.e., we are calculating the standard deviation, and the sample is small, n = 12.

First, we calculate mean of the sample:

$\overline{x}=\frac{\Sigma x}{n}$

$\overline{x}=\frac{2.31=2.09+...+1.97+2.02}{12}$

$\overline{x}=$ 2.08

Now, we estimate standard deviation:

$s=\sqrt{\frac{\Sigma (x-\overline{x})^{2}}{n-1} }$

$s=\sqrt{\frac{(2.31-2.08)^{2}+...+(2.02-2.08)^{2}}{11} }$

s = 0.1564

For t-score, we need to determine degree of freedom and $\frac{\alpha}{2}$ :

df = 12 - 1

df = 11

$\alpha$ = 1 - 0.95

α = 0.05

$\frac{\alpha}{2}=$ 0.025

Then, t-score is

$t_{11,0.025}$ = 2.201

The interval will be

$\overline{x}$ ± $t.\frac{s}{\sqrt{n} }$

2.08 ± $2.201\frac{0.1564}{\sqrt{12} }$

2.08 ± 0.099

The 95% two-sided CI on the mean is 1.981 < μ < 2.18.

B. We are 95% confident that the true population mean for this clinic is between 1.981 and 2.18. Since the mean number performed by all clinics has been 1.95, and this mean is less than the interval, there is evidence that this particular clinic performs more scans than the overall system average.

8 0

3 years ago

Gina Chuez has considered starting her own custom greeting card business. With an initial start up cost of $1500, she figures it

Digiron [165]

1.70 - 0.45 = 1.25

1500 ÷ 1.25 = 1200

Gina must sell 1200 cards before she can make a profit

6 0

3 years ago

Jake mowed 216 sq.yd. of lawn in 3 hr. Ricky mowed 108 sq.yd. of lawn in 2 hr.

algol13

Answer:

108 Square Yards

2 Hours

Step-by-step explanation:

<h2><u>PLEASE MARK BRAINLIEST</u></h2>

All you do is look at the question and it says he mowed 108 square yards in 2 hours.

8 0

3 years ago

Read 2 more answers

In a statistics class, the standard deviation of the heights of all students was 3.8 inches. The standard deviation of the heig

goblinko [34]

Answer:

The reason why standard deviation of the entire class is greater than standard deviation of males and females considered separately, is that mean values for males and females are different from each other.

Step-by-step explanation:

The concept of mean is well represented by the following formula

mean = $\frac{(x1 + x2 + x3 + ..... + xn)}{N}$ , where x1, x2, xn are the observations and N is the number of observations (population).

Standard deviation represents the distance between each observation and the mean of the population (all observations). The formula for this parameter is:

Standard deviation =√[((x1 - x)² + (x2-x)² + ....+ (xn-x)²)/N-1], where x1, x2,..., xn are the observations and x is the mean value.

In this case you have that each height registered is an observation and the number of observations represents the N value. As you can see if the mean for males is different from that of females their standard deviation will be different too. Usually males have heigths greater than that of females (1.77 vs 1.64, in USA for example), and heights inside each group will be more similar than between groups. Then, when you mix all observation there will be an increase in standard deviation, because you are mixing very different heigths

4 0

3 years ago

Four students spoke to the Home and School parents for a total of 2/3 hour. Each student spoke for the same amount of time. How

xeze [42]

creo que la respuesta el 10 minutos, porque dice "horas" pero no dice a cuantas horas equivale :) espero que te aya adudado auque sea un poquito

8 0

3 years ago