It’s a little complicated but here’s how it works:
Imagine a table with the intervals
0:4 , 4:6 , 6:7 , 7:10 , 10:13 (10 year intervals)
Then we have different rows
Class width: 4 , 2 , 1 , 3 , 3
Freq density: 0.2 , 0.5 , 1.2 , 0.7 , 0.3
So now calculate frequency where freq = class width * density
Freq: 0.8 , 1 , 3.6 , 2.1 , 0.9
So to find median find cumulative frequency
(Add all freq)
Cfreq = 8.4 now divide by 2 = 4.2
So find the interval where 4.2 lies.
0.8 + 1 = 1.8 + 3.6 = 5.6
So 4.2 (median) will lie in that interval 60-70 years.
Answer:
c
Step-by-step explanation:
You would multiply 2 1/2 and 3 3/4, which would give you 9.375 or as a mixed number 9 7/8
Answer: - 8
Step-by-step explanation:
3+(−4)−8−(−1)
3 - 4 - 8 + 1
3 - 12 + 1
-9 + 1
- 8
Raise 10 to the power of 6 to get 1000000