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Kazeer [188]
3 years ago
7

Harry estimate that his dinner will have 48g of fat her total allowance is 70g what percentage of her total daily allowance of f

at be round your answer to a whole number
Mathematics
2 answers:
boyakko [2]3 years ago
7 0
Х = 48 * 100 : 70 - <span>the proportion
х = 67 g is </span>her total daily allowance of fat 
lisov135 [29]3 years ago
3 0

Answer: about 69%

Step-by-step explanation:

Given: Total allowance of fat = 70 g

The amount of fat estimated by Harry in his dinner= 48 g

Now, the percentage of her total daily allowance of fat is given by :-

\dfrac{\text{Fat in Food}}{\text{Total allowance of fat}}\times100\\\\=\dfrac{48}{70}\times100=68.571428\approx69\%

Hence, his dinner will have about 69% of her total daily allowance of fat .

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WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

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IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

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7 0
4 years ago
How do I solve this question?
Sati [7]

Answer:

m=2 and n=3

Step-by-step explanation:

<u>Step</u> :-

Given  [ 2 x^{n}y^{2} ]^m = 4 x^6 y^4

using algebraic formula (a^m)^n= a^{mn}

now

2^{m} x^{mn} y^{2m} = 4x^{6} y^{4}

now equating 'x' powers, we get

x^{mn} = x^{6}

mn=6 ....(1)

now

y^{2m} = y^{4}

Equating 'y' powers ,we get

2 m=4

m=2

substitute m= 2 in equation (1)

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verification:-

substitute m=2 and n=3 , we get

[ 2 x^{n}y^{2} ]^m = 4 x^6 y^4

(2 x^{3} y^2)^2 = 4 x^6 y ^4\\

4 x^6 y^4 = 4 x^6 y^4

both are equating so m= 2 and n=3

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(P.S my work is shown below)

8 0
3 years ago
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