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GrogVix [38]
3 years ago
15

Which sets of numbers are closed under addition?

Mathematics
1 answer:
8_murik_8 [283]3 years ago
4 0
I would have to go with B as your answer 
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Need answer please help
PtichkaEL [24]

Answer:

-2/5

Step-by-step explanation:

3 0
3 years ago
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Hard question but would help me out
Alekssandra [29.7K]

Answer:

Critical value f(1)=2.

Minimum at (1,2), function is decreasing for 0 and increasing for x>1.

\left(3,\dfrac{4}{\sqrt{3}}\right) is point of inflection.

When 0<x<3, function is concave upwards and when x>3, , function is concave downwards.

Step-by-step explanation:

1. Find the domain of the function f(x):

\left\{\begin{array}{l}x\ge 0\\x\neq 0\end{array}\right.\Rightarrow x>0.

2. Find the derivative f'(x):

f'(x)=\dfrac{(x+1)'\cdot \sqrt{x}-(x+1)\cdot (\sqrt{x})'}{(\sqrt{x})^2}=\dfrac{\sqrt{x}-\frac{x+1}{2\sqrt{x}}}{x}=\dfrac{2x-x-1}{2x\sqrt{x}}=\dfrac{x-1}{2x^{\frac{3}{2}}}.

This derivative is equal to 0 at x=1 and is not defined at x=0. Since x=0 is not a point from the domain, the crititcal point is only x=1. The critical value is

f(1)=\dfrac{1+1}{\sqrt{1}}=2.

2. For 0 the derivative f'(x)<0, then the function is decreasing. For x>1, the derivative f'(x)>0, then the function is increasing. This means that point x=1 is point of minimum.

3. Find f''(x):

f''(x)=\dfrac{(x-1)'\cdot 2x^{\frac{3}{2}}-(x-1)\cdot (2x^{\frac{3}{2}})'}{(2x^{\frac{3}{2}})^2}=

=\dfrac{2x^{\frac{3}{2}}-2(x-1)\cdot \frac{3}{2}x^{\frac{1}{2}}}{4x^3}=\dfrac{2x^{\frac{3}{2}}-2\cdot\frac{3}{2}x^{\frac{3}{2}}+ 2\cdot\frac{3}{2}x^{\frac{1}{2}}}{4x^3}=

=\dfrac{-x+3}{4x^{\frac{5}{2}}}.

When f''(x)=0, x=3 and f(3)=\dfrac{3+1}{\sqrt{3}}=\dfrac{4}{\sqrt{3}}.

When 0<x<3, f''(x)>0 - function is concave upwards and when x>3, f''(x)>0 - function is concave downwards.

Point \left(3,\dfrac{4}{\sqrt{3}}\right) is point of inflection.

4 0
3 years ago
Find the number of terms for this polynomial.<br> 3
Natalka [10]

Answer:

Im sorry, im not in high school yet :(

Step-by-step explanation:

:( wish i could help :(

8 0
3 years ago
CC=\frac{5}{9}(F - 32)
PSYCHO15rus [73]
The answer would be D I and II only

My work:
The only answer that has both statement I and statement II as true is D<span>, but if you have time and want to be absolutely thorough, you can also check to see if statement III is true </span>
5 0
3 years ago
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Using diagonals from a common vertex, how many triangles could be formed from the polygon pictured below?
Ad libitum [116K]

9514 1404 393

Answer:

  3

Step-by-step explanation:

From a given vertex, two of the vertices are adjacent, so a "diagonal" to those will not form a triangle. The number of diagonals that can be drawn is 3 fewer than the number of sides. The number of triangles is 1 more than the number of diagonals.

For a 5-sided figure, 2 diagonals can be drawn from a common vertex.

  3 triangles will be formed.

8 0
3 years ago
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