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2 years ago

5

There are some cubes in a bag.

1 answer:

dedylja [7]2 years ago

8 0

1:5 is the answer in 1:n form

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Drag each tile to the correct box. not all tiles will be used.

lana66690 [7]

Answer:

$y=\frac{13}{6}x$ $y= \frac{11}{5}x$ $y = \frac{21}{9}x$ $y = \frac{19}{8}x$

Step-by-step explanation:

Given

The attached graph

Required

Equations with higher unit rate

First, calculate the unit rate of the graph

$m = \frac{y_2 - y_1}{x_2 - x_1}$

Where:

$(x_1.y_1) = (0,0)$

$(x_2.y_2) = (7,15)$

So:

$m = \frac{15 - 0}{7 - 0}$

$m = \frac{15}{7}$

$m = 2.143$

For the given options.

The unit rate is the coefficient of x

So: $y = \frac{19}{8}x$

Going by the above definition of unit rate.

$m = \frac{19}{8}$

$m = 2.375$

$y = \frac{27}{13}x$

$m = \frac{27}{13}$

$m = 2.077$

$y = \frac{21}{9}x$

$m = \frac{21}{9}$

$m = 2.333$

$y= \frac{11}{5}x$

$m= \frac{11}{5}$

$m= 2.20$

$y = \frac{15}{7}x$

$m = \frac{15}{7}$

$m = 2.143$

$y = \frac{31}{15}x$

$m = \frac{31}{15}$

$y = 2.067$

$y=\frac{13}{6}x$

$m=\frac{13}{6}$

$m=2.167$

The unit rates grater than the graph's from small to large are:

$y=\frac{13}{6}x$ $y= \frac{11}{5}x$ $y = \frac{21}{9}x$ $y = \frac{19}{8}x$

$m=\frac{13}{6}$ $m= \frac{11}{5}$ $m = \frac{21}{9}$ $m = \frac{19}{8}$

4 0

3 years ago

Read 2 more answers

A commuter crosses one of three bridges, A, B, or C, to go home from work. The commuter crosses bridge A with probability 1/3, c

mihalych1998 [28]

Answer:

0.1333 = 13.33% probability that bridge B was used.

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

$P(B|A) = \frac{P(A \cap B)}{P(A)}$

In which

P(B|A) is the probability of event B happening, given that A happened.

$P(A \cap B)$ is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Arrives home by 6 pm

Event B: Bridge B used.

Probability of arriving home by 6 pm:

75% of 1/3(Bridge A)

60% of 1/6(Bridge B)

80% of 1/2(Bridge C)

So

$P(A) = 0.75*\frac{1}{3} + 0.6*\frac{1}{6} + 0.8*\frac{1}{2} = 0.75$

Probability of arriving home by 6 pm using Bridge B:

60% of 1/6. So

$P(A \cap B) = 0.6*\frac{1}{6} = 0.1$

Find the probability that bridge B was used.

$P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.1}{0.75} = 0.1333$

0.1333 = 13.33% probability that bridge B was used.

8 0

3 years ago

I need help with a geometry question

Natali [406]

Lines a and b are parallel, and lines c and d are parallel

7 0

2 years ago

Can Sombody help me fast will mark brainliest

densk [106]

Answer:

2950

Step-by-step explanation:

3 0

2 years ago

Please give an explanation on how you got this answerI'm not sure if it's too late or what, but I can't get it.

Alona [7]

Step 1: multiple the second equation by 2 so that you get -1/4 for the coefficient of y, the same as in equation 1
equation 2 multiply by 2: 1/4 x - 1/4 y=38 ..........name this equation 3
subtract equation 1 from equation 3: (1/4 x -1/2 x)=38-10
-1/4 x = 28
x=-112
plug in x=-112 in any of the equation, you will get y=-264
so the answer is A

8 0

2 years ago