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Marina86 [1]
2 years ago
14

Which binomial is a factor of the polynomial? x2 - 6x + 9 A) (x - 9) B) (x + 3) C) (x + 9) D) (x - 3)

Mathematics
1 answer:
ICE Princess25 [194]2 years ago
8 0

x^2-6x+9=x^2-3x-3x+9=x(x-3)-3(x-3)=(x-3)(x-3)\\\\Answer:\ \boxed{D)\ (x-3)}

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I think its C. but Im not sure how to determine the answer, however I know that using the two points I picked... (0, 2) & (-
9966 [12]
It is B.

You see that the line segment crosses the y-axis at 1? That is known as the y intercept.

Remember y = mx + b?

Well in this graph, b = 1
Therefore it is B
3 0
3 years ago
Read 2 more answers
Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that
Maksim231197 [3]

Complete Question

The Brown's Ferry incident of 1975 focused national attention on the ever-present danger of fires breaking out in nuclear power plants. The Nuclear Regulatory Commission has estimated that with present technology there will be on average, one fire for every 10 years for a reactor. Suppose that a certain state has two reactors on line in 2020 and they behave independently of one another. Assuming the incident of fires for individual reactors can be described by a Poisson distribution, what is the probability that by 2030 at least two fires will have occurred at these reactors?

Answer:

The value is P(x_1 + x_2 \ge 2 )= 0.5940

Step-by-step explanation:

From the question we are told that

     The rate at which fire breaks out every 10 years is  \lambda  =  1

  Generally the probability distribution function for Poisson distribution is mathematically represented as

               P(x) =  \frac{\lambda^x}{ k! } * e^{-\lambda}

Here x represent the number of state which is  2 i.e x_1 \ \ and \ \ x_2

Generally  the probability that by 2030 at least two fires will have occurred at these reactors is mathematically represented as

          P(x_1 + x_2 \ge 2 ) =  1 - P(x_1 + x_2 \le 1 )

=>        P(x_1 + x_2 \ge 2 ) =  1 - [P(x_1 + x_2 = 0 ) + P( x_1 + x_2 = 1 )]

=>        P(x_1 + x_2 \ge 2 ) =  1 - [ P(x_1  = 0 ,  x_2 = 0 ) + P( x_1 = 0 , x_2 = 1 ) + P(x_1 , x_2 = 0)]

=>  P(x_1 + x_2 \ge 2 ) =  1 - P(x_1 = 0)P(x_2 = 0 ) + P( x_1 = 0 ) P( x_2 = 1 )+ P(x_1 = 1 )P(x_2 = 0)

=>    P(x_1 + x_2 \ge 2 ) =  1 - \{ [ \frac{1^0}{ 0! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]] )+ ( [ \frac{1^1}{1! } * e^{-1}] * [[ \frac{1^1}{ 1! } * e^{-1}]] ) + ( [ \frac{1^1}{ 1! } * e^{-1}] * [[ \frac{1^0}{ 0! } * e^{-1}]]) \}

=>   P(x_1 + x_2 \ge 2 )= 1- [[0.3678  * 0.3679] + [0.3678  * 0.3679] + [0.3678  * 0.3679]  ]

P(x_1 + x_2 \ge 2 )= 0.5940

               

3 0
2 years ago
A principal of $2600is invested at 6.75% interest, compounded annually. How much will the investment be worth after 14 years
dedylja [7]

Answer:

$6488.19

Step-by-step explanation:

To solve this problem we use the compounded interest formula:

amount  =  principal(1 + (r \n))^({n}{t})

a = $2600(1+(0.0675/1))¹*¹⁴

a = $6488.19

8 0
3 years ago
a local hamburger shop sold a combined total of 616 hamburgers and cheeseburgers on sunday. there were 66 moore cheeseburgers so
Ksju [112]

Answer:

242 Hamburgers,  374 Cheeseburgers

Step-by-step explanation:

Step 1: 616/2-66=242 Hamburgers

Step 2: 616-242=374 Cheeseburgers

Step 3: Check Work 242+374=616

4 0
2 years ago
Will give barinliest. I need help Now.
Aloiza [94]

Answer:

im pretty sure its N = w^2 + 2w

hope this helps if it does plz brainliest :)

Step-by-step explanation:

4 0
3 years ago
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