Yes, I will list acute first (<90) and obtuse second (>90) and they need to add to 180
10 and 170
20 and 160
30 and 150
40 and 140
50 and 130
60 and 120
70 and 110
80 and 100 and so on
Answer:
The height of deepness of submarine is 424.1 feet
Step-by-step explanation:
Given as :
The angle at which submarine drives of the surface of water = Ф = 13°
The speed at which submarine travel = s = 760 feet per minute
Let The height of deepness of submarine = h feet
The time taken to reach that deepness = t = 5 minutes
<u>According to question</u>
The height of deepness of submarine = 
i.e h × cos(90 - Ф) = 
Or, h × Sin(Ф) = 
Or, h × Sin(13°) = 95 feet
Or, h × 0.224 = 95 feet
∴ h = 
i.e h = 424.10 feet
So, The height of deepness of submarine = h = 424.10 feet
Hence, The height of deepness of submarine is 424.1 feet Answer
Answer:
Micheal could rewrite the equation as negative 8 + negative 3 and move 3 spaces to the left.
Step-by-step explanation:
-8 - 3 = -8 + (-3)
<h2>1210 cubic feet</h2>
Step-by-step explanation:
Initial dimensions of the storeroom were
length,
width and
height.
The room is in the shape of a cuboid. Volume of a cuboid =
, where
are the length, width and height of the cuboid.
So, Volume of storeroom initially = 
Finally, the length was increased to
and width to
.
Final volume of storeroom = 
Increase in volume = 
∴ 1210 cubic feet of storage was added.