Answer:
The coach can do this in 3,003 ways
Step-by-step explanation:
Here, the coach needs to select a team of 5 from a total of 15 players
Mathematically, the number of ways this can be done is simply 15 C5 ways
Generally, if we are to select a number of r items from n items, this can be done in nCr ways = n!/(n-r)!r!
Applying this to the situation on ground, we have;
15C5 = 15!/(15-5)!5! = 15!/10!5! = 3,003 ways
Answer:
The smallest possible length is 0.83m
Step-by-step explanation:
Given
Required
The smallest length of the tank
Since the tank is cubical, then the volume is:
This gives:
Express as 
Take cube roots of both sides
Rewrite as:
Approximate
I think its letter D because x + 2y fits with the equation and there for -3
<span>$100.00 rounded value
$105.00 rounded value
$110.00 rounded value
For example,
14,494 </span>
<span>To round off the height value to the nearest thousand we can use the expanded from to clarity the position of numbers which is: </span>
<span>10, 000 = ten thousand </span>
<span>4, 000 = thousands </span>
<span>400 = hundreds </span>
<span>90 = tens </span>
<span>4 = ones </span>
<span>Here we can notice than four thousand is the value where the nearest thousands is placed. Hence we can round off the number of 14, 494 into 14, 000. Notice 0-4 rounding off rules.<span>
</span></span>
20 divided by 4 is 5 so
4$ will be for pay as you go.
5$ will be for regular deal
4+5=9 so the all in one deal is 9$
