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Zigmanuir [339]
4 years ago
12

85001 to nearest ten thousand

Mathematics
2 answers:
Leokris [45]4 years ago
5 0
85001 rounded to the nearest ten thousand is 90,000. Because there is a 5 in the thousands place, the 8 in the ten thousands place rounds up to 9. Always use the numeral to the right of the place value you are rounding. If it is 5 or greater the number increases. If it is less than 5, it remains the same.
poizon [28]4 years ago
4 0
First ask yourself what is the ten thousands ? If its 8 then your right . now ask what is on the left of 8 ? On the left of 8 is 5 . If the number 1-4 are on the left then dont change the ten thousands but if it is 5-6 then add +1 to the number to be rounded off . So now the answer is 95001 . But what you are going To do next is your going to make all the numbers on the left of 8 be 0 . But dont mind then numbers on the right of the number to be rounded off . Therefore the answer is 90000.
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Find the value of cos J rounded to the nearest hundredth, if necessary.
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\green{\huge{\red{\boxed{\green{\mathfrak{QUESTION}}}}}}

Find the value of cos J rounded to the nearest hundredth

\bold{ \red{\star{\blue{GIVEN }}}}

HYPOTHESES= 13

PERPENDICULAR= 12

BASE = ?

\bold{\blue{\star{\red{TO \:  \: FIND}}}}

\cos(j)  =  ?

\bold{  \green{ \star{ \orange{FORMULA \:  USED}}}}

  1. PYTHAGORAS THEROM
  2. \cos(j) =  \frac{ BASE}{HYPOTENUSE}

\huge\mathbb{\red A \pink{N}\purple{S} \blue{W} \orange{ER}}

<h2>FOR BASE:- </h2>

{h}^{2}  =  {p}^{2}  +  {b}^{2}

{13}^{2}  =  {12}^{2}  +  {x}^{2}  \\ 169 - 144 =  {x}^{2}  \\ 25 =  {x}^{2}  \\  \sqrt{25}  = x \\ 5 = x = base

<h2>NOW :- </h2>

\cos(j) =  \frac{ BASE}{HYPOTENUSE}

\cos(j)  =  \frac{5}{13}  \\  \cos(j)  = 0.34

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