probability of one go on vacation and one does not go on vacation is 0.2356 and probability none of them go on vacation is 0.1444
According to a survey, 62% of americans go on vacation each .
two americans are chosen from a group of 100 americans.
what is the probability that one or both of the people chosen does not go on vacation each ?
62% americans go on vacation t
hen 38% americans does not go on vacation
Total group of americans is 100
out of 100 americans 62 go on vacation and 38 does not go on vacation
probability of one go on vacation and one does not go on vacation
= 0.62*0.38
=0.2356
probability none of them go on vacation
= 0.38*0.38
=0.1444
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Answer:
99 (cm^2)
Step-by-step explanation:
Perpendicular to the AB segment at points D and C, the graph is divided into two triangles and a rectangle.
The area of the middle rectangle is equal to 8*9=72. The hypotenuse of the right triangle is 10cm, and one of the right sides is 9cm, so the other side is SQRT (10^2-9^2) = SQRT (19).
One side of the left triangle is 9cm long and the other side is 14-8-sqRT (19) = 6-sqRT (19) cm.
Then, add the area of the three parts.
72+9*sqrt（19）/2+9*（6-sqrt（19））/2=99 (cm^2)
The answer is C.
explanation: you turn 1/3 into a decimal and that will be 0.333. Then you multiply 0.333 with 82,000 and that gets you C
have a great day :) hope this helped.
Answer:
About $0.11
This is because 0.11 is how much money one pack is Worth.
Answer:
Step-by-step explanation:
The rule of reflecting over the x-axis is that point (x, y) →( x, -y) so
Q'(1, -3), R'(-2,-6),and S'(-1,-1) reflected over the x-axis, become
Q"(1, 3), R"(-2, 6), and S"(-1, 1) .
