Question

7+4(5-3) to the second power + 9/3

Answer 1

So to simplify this, we have the equation:

$(7+4(5-3))^{2}+\frac{9}{3}$

Using PEMDAS, we can solve for what's in the parentheses:

$(7+4(2))^{2}+\frac{9}{3}$

$(7+8)^{2}+\frac{9}{3}$

$(15)^{2}+\frac{9}{3}$

Then we can solve the exponential part:

$225+\frac{9}{3}$

And we know that $\frac{9}{3}$ is equal to 3, so we can solve completely:

$225+3=228$

So the answer is 228.