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Dvinal [7]
3 years ago
11

Two lines and a point are guaranteed to be coplanar If..

Mathematics
2 answers:
Roman55 [17]3 years ago
8 0
Two lines and a point are guaranteed to be coplanar if the two lines share only a single point.

Hope this helped :)
Zielflug [23.3K]3 years ago
8 0

Answer:

Two lines and a point are said to be coplanar if the two lines share only a single point.

Step-by-step explanation:

A line is a one dimensional figure such that it has no thickness. Plane is a two dimensional figure which actually extends infinitely .

Points are said to be coplanar if they lie on same plane and lines are said to be coplanar if they lie in the same plane.

We need to find the condition under which two lines and a point are coplanar .

Two lines and a point are said to be coplanar if the two lines share only a single point.

So, option b. is correct i.e., they lie in the same plane .

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During a birthday party, 1/4 drank fanta orange, 1/3 took coca cola 1/5 of the remainder drank sprite and the rest took krest wh
Licemer1 [7]

Answer:

1/12

Step-by-step explanation:

Since 1/4 drank fanta orange and 1/3 took coca cola, the. remainder will be:

= 1 - (1/4 + 1/3)

= 1 - 7/12

= 5/12

Therefore, 1/5 of the remainder drank sprite, the fraction that drank sprite will be:

= 1/5 × 5/12

= 1/12

3 0
2 years ago
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mash [69]

Answer:

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Step-by-step explanation:

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3 years ago
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Answer:

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Step-by-step explanation:

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4 0
3 years ago
Daniel is making a cube using blocks. The cube is solid and has no holes.
cestrela7 [59]
Its d 729 because on 1 layer theres are 81 cubes and there are 9 layers so 81 times 9 equals 729

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4 0
3 years ago
Read 2 more answers
Type the correct answer in each box. Use numerals instead of words. If necessary, use / for the fraction bar(s).
GrogVix [38]

Answer:

  1. D. f^-1(x) = log2(x -6)
  2. 4x^2 -3 . . . . x ≤ 0
  3. B. √(x^5) -3√(x^3) -18√x

Step-by-step explanation:

1. When you replace f(x) by x and x by y, you have

... x = 2^y + 6

The first thing you do is subtract 6; then you take the base-2 logarithm:

... (x -6) = 2^y

... log2(x -6) = y = f^-1(x)

You know that to get the y-term by itself, you must subtract 6. Anything else you do will operate on (x-6). Only answer choice D has that sort of construction.

2. When you swap x and y and solve for y, you have ...

... x = -1/2√(y+3)

... -2x = √(y +3) . . . . . . multiply by -2

... (-2x)^2 = y +3 . . . . . square

... 4x^2 - 3 = y = f^-1(x) . . . . subtract 3

The range of f(x) is (-∞, 0], so that is the domain of f^-1(x). That is, f^-1(x) is defined for x ≤ 0.

3. The product of the two functions is ...

... (x -6)(√x)(x +3) = (√x)(x^2 -3x -18)

<em>Every term</em> will have a factor of √x, and the coefficients will be 1, -3, -18. Only selection B matches those conditions.

7 0
3 years ago
Read 2 more answers
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