A rectangle is 12 cm long and 9 cm wide. Its diagonal is labeled 2x - 11. What is the value of x?
2 answers:
Answer: 13
<u>Step-by-step explanation:</u>
Use Pythagorean Theorem to find the length of the diagonal (aka hypotenuse) which is also equal to 2x - 11.
12² + 9² = hypotenuse²
144 + 81 = hypotenuse²
144 + 81 = (2x - 11)²
225 = (2x - 11)²
√225 = √(2x - 11)²
15 = 2x - 11
<u> +11 </u> <u> +11 </u>
26 = 2x
<u> ÷2 </u> <u>÷2 </u>
13 = x
Answer: The value of x is 13 cm.
Explanation:
It is given that the length and width of the rectangle are 12 cm and 9 cm.
Use pythagoras to find the value of the diagonal.





It is given that the diagonal is labeled as 2x-11.



Divide both side by 2.

Therefore, x = 13cm.
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Step-by-step explanation:
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A = s^2
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Now we can subtract:
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Sorry if I spelled some words wrong
I’m ok lots of school work