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dolphi86 [110]
3 years ago
15

A rectangle is 12 cm long and 9 cm wide. Its diagonal is labeled 2x - 11. What is the value of x?

Mathematics
2 answers:
Anton [14]3 years ago
4 0

Answer: 13

<u>Step-by-step explanation:</u>

Use Pythagorean Theorem to find the length of the diagonal (aka hypotenuse) which is also equal to 2x - 11.

12² + 9² = hypotenuse²

144 + 81 = hypotenuse²

144 + 81 = (2x - 11)²

    225 = (2x - 11)²

 √225 = √(2x - 11)²

     15   = 2x - 11

<u>    +11  </u>    <u>     +11 </u>

     26  = 2x

   <u>  ÷2  </u>  <u>÷2  </u>

      13  = x

shusha [124]3 years ago
3 0

Answer: The value of x is 13 cm.

Explanation:

It is given that the length and width of the rectangle are 12 cm  and 9 cm.

Use pythagoras to find the value of the diagonal.

Hypotenuse=\sqrt{(base)^2+(perpendicular)^2}

D=\sqrt{(12)^2+(9)^2}

D=\sqrt{144+81}

D=\sqrt{225}

D=15

It is given that the diagonal is labeled as 2x-11.

2x-11=15

2x=15+11

2x=26

Divide both side by 2.

x=13

Therefore, x = 13cm.

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