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4 years ago

X+y=1 show work and graph it please. and use x/y.

1 answer:

6 0

You will put x=0 and calculate the value of y=1 and then put y=0 and get value of x=1 and then put x=1 and get value of y=0 and then put y=1 and get x and so one , finally you could plot the graph.

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Convert 2 inches into centimeters. Round your answer to the nearest tenth.

kobusy [5.1K]

Answer:

5.1 centimeters (5.08 not rounded)

Step-by-step explanation:

1 inch=2.54 centimeters

2.54*2=5.08

7 0

3 years ago

Y=x y=0 x=2 x=4 about x=1

Reil [10]

Yes this is correct.

7 0

4 years ago

You would like to have $500,000 when you retire in 35 years. How much should you invest each quarter if

LenKa [72]

Answer:

$201,855.65136317

Step-by-step explanation:

A= $500000 P= ? R = 2.6 N = 35*4= 140

A= P(1+R/4*100)^4n

$500000 = P(1+2.6/400)^140

$500000 = P(402.6/400)^140

$500000 = P* 2.4770175946196

500000/2.4770175946196 = P

$201,855.65136317 = P

I did it using calculator for great precision.

Thank you

4 0

3 years ago

How to subtract the fractions

jenyasd209 [6]

Get a common denominator. Then subtract the numberators

5 0

4 years ago

A normal distribution is observed from the number of points per game for a certain basketball player. If the mean is 16 points a

Hatshy [7]

Answer:

The probability that in a randomly selected game, the player scored between 12 and 20 points is 95%.

Step-by-step explanation:

Given information: The population mean is 16 and standard deviation is 2.

We need to find the probability that in a randomly selected game, the player scored between 12 and 20 points.

$P(12$

$12=16-2(2)=\mu-2\sigma$

$20=16+2(2)=\mu+2\sigma$

So, we need to find the value of

$P(\mu-2\sigma$

According to the empirical rule:

$P(\mu-\sigma$

$P(\mu-2\sigma$

$P(\mu-3\sigma$

Using the empirical rule, we get

$P(\mu-2\sigma$

$P(12$

Therefore the probability that in a randomly selected game, the player scored between 12 and 20 points is 95%.

4 0

3 years ago