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Jet001 [13]
3 years ago
5

Put the following equation of a line into slope-intercept form, simplifying all

Mathematics
1 answer:
ANTONII [103]3 years ago
8 0
Answer and solution below:

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Bozbehisbdhjsvsujsbsvwkhelpmenowbkfjfhdi
Lana71 [14]
Cuboid C is 4 and 4. Cuboid D is 2 and 4.
6 0
2 years ago
Solve(x+y)^2=(x^2-2xy+y^2) and show your work
Shtirlitz [24]

(x + y)^2 = (x^2 - 2xy + y^2)

First distribute the ^2 on the left side of the equation to each term inside the parenthesis:

x^2+ 2xy + y^2

Now pick one of the variables to solve for and isolate it:

(solving for x)

x^2 + 2xy + y^2 = x^2 - 2xy + y^2

x^2+ 2xy = x^2 - 2xy

2xy = -2xy

-x = x

x = 0

When you solve for y in the equation it will turn out to be 0 as well

7 0
3 years ago
Read 2 more answers
The ticket for ice hockey match was £14.50. the price has increased by 7%.
Serjik [45]
(14.50×7)/100 + 14.50
7 0
3 years ago
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What is the answer for:<br> 1÷6 + √3
NikAS [45]

1.89871747424 heres the answer

3 0
2 years ago
Read 2 more answers
Please help me. these problems<br>​
jeyben [28]

Answer:

1st problem:

Converges to 6

2nd problem:

Converges to 504

Step-by-step explanation:

You are comparing to \sum_{k=1}^{\infty} a_1(r)^{k-1}

You want the ratio r to be between -1 and 1.

Both of these problem are so that means they both have a sum and the series converges to that sum.

The formula for computing a geometric series in our form is \frac{a_1}{1-r} where a_1 is the first term.

The first term of your first series is 3 so your answer will be given by:

\frac{a_1}{1-r}=\frac{3}{1-\frac{1}{2}}=\frac{3}{\frac{1}{2}=6

The second series has r=1/6 and a_1=420 giving me:

\frac{420}{1-\frac{1}{6}}=\frac{420}{\frac{5}{6}}=420(\frac{6}{5})=504.

3 0
3 years ago
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