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Lubov Fominskaja [6]
3 years ago
12

80.3 time 0.58 must show work

Mathematics
1 answer:
baherus [9]3 years ago
6 0
Answer:46.574 it's simple multiplication
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Solve the equation. 3x + 5 = x - 3
Luden [163]

Answer:

x=-4

Step-by-step explanation:

Subtract x from 3x ( 2x )

2x+5=-3

Subtract 5 from -3 ( -8 )

2x=-8

Divide ( -4 )

x=-4

3 0
2 years ago
Alice drives to Alabama at a rate of 60pmh. She drives home at a rate of 40mph. If the total trip takes her 5 hours, how long do
jonny [76]
OK, so she definitely drove home faster than when she drove to her first destination. So she must've taken quicker to get home. Lets assume 3 hours on the way there and 2 hours on the way back.
I really hoped this helped. I'm no genius, but you asked for help and I tried to give it.
Have a great day.
6 0
3 years ago
Can somebody please get me the answer to this?
Advocard [28]

Answer:

x = 15 , y = 105 ,z= 105

Step-by-step explanation:

i dont think you need explanation for all this

7 0
2 years ago
A sign standing 6 feet tall is situated 18 feet away from a flag pole. at a certain time of day the sign's shadow is 3 feet long
alexdok [17]
Observe attached picture.

On picture we have:
A = height of flagpole = x ft
B = length of flagpole's shadow = 24 ft
C = height of sign = 6 ft
D = length of sign's shadow = 3 ft

When we draw a picture representing this problem we can also add another line marked in red. This way we can see that we have two right-angle triangles. We can see that both have same angle marked with α.

We can apply trigonometry rules to find height of flagpole.

From small triangle containing sign we can find tangens function:
tan \alpha = \frac{C}{D}
Similarly we can do for large triangle containing flagpole:
tan \alpha = \frac{A}{B}

We see that these two equations have same left sides. This means that their right sides must also be same:
\frac{C}{D} = \frac{A}{B}
We can solve for A:
CB=AD \\ A= \frac{CB}{D}  \\ A= \frac{6*24}{3}  \\ A=48 ft

Height of flagpole is 48 feet.

8 0
3 years ago
6. Regroup the numbers in the following problems, putting the numbers that add up to 10 or a multiple of 10 in parentheses.
svetoff [14.1K]

Answer:

a) (2+8)+9

b) (3+7)+5+4

c) (4+16)+2

d) (31+9)+4

Step-by-step explanation:

a) 2+9+8

2 and 8 add up to 10, so we regroup them in parentheses

(2+8)+9


b) 3 + 5 + 4 + 7

3 and 7 add up to 10, so we regroup them in parentheses

(3+7)+5+4


c) 4 + 2 + 16

4 and 16 add up to 20 which is a multiple of 10, so we regroup them in parentheses

(4+16)+2


d) 31 + 4 + 9

31 and 9 add up to 40 which is a multiple of 10, so we regroup them in parentheses

(31+9)+4

4 0
3 years ago
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