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djyliett [7]
4 years ago
13

Martha tries to exercise at least 30 minutes eac day write an inequality to represent the number of minutes Martha exercises eac

h day
Mathematics
1 answer:
Sergio [31]4 years ago
4 0
Let “t” represent the number of minutes Martha exercises each day. If she needs to exercise *at least* 30 minutes, t has to be equal to or greater than 30, so our inequality would be

t ≥ 30
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Vic is standing on the ground at a point directly south of the base of the CN Tower and can see the top when looking at an angle
Sindrei [870]

The angle of elevation of 61° and 72° with the height of the tower being 553.3 m. gives Vic's distance from Dan as approximately 356 meters.

<h3>How can the distance between Vic and Dan be calculated?</h3>

Location of Vic relative to the tower = South

Vic's sight angle of elevation to the top of the tower = 61°

Dan's location with respect to the tower = West

Dan's angle of elevation in order to see the top of the tower = 72°

Height of the tower = 553.3m

tan( \theta) =  \frac{opposite}{adjacent}

tan( 61 ^{ \circ}) =  \frac{553.3}{ Vic' s\: distance \: to \: tower}

distance  =  \frac{553.3}{tan ( {61}^{ \circ} )}  = 306.7

  • Vic's distance from the tower ≈ 306.7 m

Similarly, we have;

Dan's distance  =  \frac{553.3}{tan ( {72}^{ \circ} )}  = 179.8

  • Dan's distance from the tower ≈ 179.8 m

Given that Vic and Dan are at right angles relative to the tower (Vic is on the south of the tower while Dan is at the west), by Pythagorean theorem, the distance between Vic and Dan <em>d </em>is found as follows;

  • d = √(306.7² + 179.8²) ≈ 356

Therefore;

  • Vic is approximately 356 meters from Dan

Learn more about Pythagorean theorem here:

brainly.com/question/343682

#SPJ1

4 0
2 years ago
DUE NOW PLEASE HELP ME
NISA [10]

Answer:

Step-by-step explanation: 16.990107955403875

•Rectangular prism - Multiply the measurement of the length times the width, then times the height  

•Cube - Since all sides are the same measurement, it would be the measurement of any side, or edge, cubed, or a³  

•Prism - Find the area of the base, then multiply the area times the height of the prism. Area would be length times width (B), or B x h  

•Triangular prism - Find the area of the base (b), then multiply the area times the length (l) between the triangular bases. Area of the base would be ½ times the base times the height (h) of the triangle, or ½bhl  

•Cylinder - Find the area of the circular face using pi times the radius squared, then multiply that area times the height of the cylinder, so πr²h  

•Pyramid - Find the area of the base and multiply that area times the height of the pyramid and multiply by 1/3, or 1/3Bh  

•Square pyramid - Find the area of the base and multiply that area times the height of the pyramid and multiply by 1/3, or 1/3s²h  

•Rectangular pyramid - Find the area of the base and multiply that area times the height of the pyramid and multiply by 1/3, or 1/3 lwh  

•Sphere - For a sphere, multiply 4/3 times pi, then time the radius cubed, or 4/3 πr³

6 0
3 years ago
Which equation has the solutions x = -3 ± √3i/2 ?
Maurinko [17]

Answer:Answer is option C : [x^{2} + 3x + 3 ] =0

Note:  None of options matches with given question.

instead of "-3" , there should be "-\frac{3}{2}".

Step-by-step explanation:

Note:  None of options matches with given question.

instead of "-3" , there should be "\frac{3}{2}".  

Here, First thing you have to observe the nature of roots.

∴ x = -\frac{3}{2}+\frac{\sqrt{3}}{2}i and x = -\frac{3}{2}-\frac{\sqrt{3}}{2}

∴ [ x+(\frac{3}{2}-\frac{\sqrt{3}}{2}i) ][ x+(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [ x^{2} + x(\frac{3}{2}+\frac{\sqrt{3}}{2}i)+ x(\frac{3}{2}-\frac{\sqrt{3}}{2}i) + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ]=0

∴ [x^{2} + \frac{3}{2}x + \frac{\sqrt{3}}{2}ix + \frac{3}{2}x - \frac{\sqrt{3}}{2}ix + (3-\frac{\sqrt{3}}{2}i)(3+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + (\frac{3}{2}-\frac{\sqrt{3}}{2}i)(\frac{3}{2}+\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{\sqrt{3}}{2}i)(\frac{\sqrt{3}}{2}i) ] =0

∴ [x^{2} + 3x + \frac{9}{4} - (\frac{3}{4}) i^{2} ] =0

∴ [x^{2} + 3x + \frac{9}{4} + (\frac{3}{4}) ] =0

∴ [x^{2} + 3x + \frac{12}{4} ] =0  

∴ [x^{2} + 3x + 3 ] =0  

Thus, Answer is option C : <em>[x^{2} + 3x + 3 ] =0  </em>

6 0
4 years ago
Find the cubic equation that has -1 and 2i as roots
ryzh [129]
The cuic equation is -1 and 2i
6 0
3 years ago
The perimeter of a television screen is 94 inches it is 17 inches tall how wide is it
Nadya [2.5K]
<h3>Answer:  30 inches</h3>

==========================================================

Explanation:

x = unknown width

For this rectangle, there are 2 sides of length x, and 2 sides of length 17.

The perimeter is P = 2x+2*17 = 2x+34

Set this equal to the given perimeter (94) and solve for x.

2x+34 = 94

2x = 94-34

2x = 60

x = 60/2

x = 30

The TV is 30 inches wide

5 0
2 years ago
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