A=1/2 ap What is the value of p if A=40ft2 and a= 8ft?

Mr. Hebert's class has 36 students and Ms. Green's class has 30 students. For a class competition, each class must be divided in

Dominik [7]

Answer: try question cove just saying

8 0

3 years ago

What is the domain and range

kogti [31]

Answer:

The domain is all the x-values, and the range is all the y-values

Step-by-step explanation:

7 0

3 years ago

patrick drank 3/4 liters of water on wednesday before going jogging and 4/5 liter of water after his jog . how much water did pa

Alona [7]

To find the total of 3/4 and 4/5 is to add them together. However, in order to add them together you need to find the least common denominator (LCD). And the LCD of both denominators would be 20, because that is the smallest number both 4 and 5 can divide into. And here is the tricky part, now you have to change the numerators. So since 3/4th's now has a denominator of 20 you have to make the 3 match the 20. So 4 times what it 20? It is 5. So now multiply 5 by three and that will give you 15/20, which can reduce to 3/4 which means that you did this correctly! Now repeat the same steps with 4/5:

4/5=4/20
20÷5=4
4•4=16
16/20 (16/20 can reduce to 4/5 which means you did this correctly.

Now to add them keep the denominators the same and only add the numerators:

15/20 + 16/20 = 31/20

Now this as a mixed number would be 1 11/20. I hope this was helpful!

4 0

3 years ago

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Joe has one book each for algebra, geometry, history, psychology, Spanish, English and Physics in his locker. How many different

Alisiya [41]

Answer:

There are 35 different sets of 3 books Joe could choose

Step-by-step explanation:

* Lets explain how to solve the problem

- Combination is a collection of the objects where the order doesn't

matter

- The formula for the number of possible combinations of r objects from

a set of n objects is nCr = n!/r!(n-r)!

- n! = n(n - 1)(n - 2)................. × 1

Lets solve the problem

- Joe has one book each for algebra, geometry, history, psychology,

Spanish, English and Physics in his locker

∴ He has seven books in the locker

- He wants to chose three of them

∵ The order is not important when he chose the books

∴ We will use the combination nCr to find how many different sets

of three books he can choose

- The total number of books is 7

∴ n = 7

∵ He chooses 3 of them

∴ r = 3

∵ 7C3 = 7!/3!(7 - 3)! = 7!/3!(4!)

∴ $7C3=\frac{(7)(6)(5)(4)(3)(2)(1)}{[(3)(2)(1)][(4)(3)(2)(1)]}=35$

∴ 7C3 = 35

* There are 35 different sets of 3 books Joe could choose

3 0

3 years ago

I need help with this problem

leva [86]

Answer:

about 2.253 centimeters

Step-by-step explanation:

3 0

2 years ago