The answer is b. 2,8 and 3,11
8=3(2)+2
8=6+2
8=8
11=3(3)+2
11=9+2
11=11
Answer:
The velocities after 739 s of firing of each engine would be 6642.81 m/s in the x direction and 5306.02 in the y direction
Step-by-step explanation:
- For a constant acceleration:
, where 
is the final velocity in a direction after the acceleration is applied, 
is the initial velocity in that direction before the acceleration is applied, a is the acceleration applied in such direction, and t is the amount of time during where that acceleration was applied. - <em>Then for the x direction</em> it is known that the initial velocity is
5320 m/s, the acceleration (the applied by the engine) in x direction is 
1.79 m/s2 and, the time during the acceleration was applied (the time during the engines were fired) of the is 739 s. Then: 
- In the same fashion, <em>for the y direction</em>, the initial velocity is
0 m/s, the acceleration in y direction is 
7.18 m/s2, and the time is the same that in the x direction, 739 s, then for the final velocity in the y direction: 
Answer:
Use your brain
Step-by-step explanation:
Answer: -1
Step-by-step explanation: Let the integer be x
It's additive inverse = -x
= x / -x = -1
(4,5)(2,1)
slope = (1 - 5) / (2 - 4) = -4/-2 = 2
(-2,3)(-4,4)
slope = (4 - 3) / (-4 - (-2) = 1/(-4 + 2) = -1/2
2 and -1/2 are negative reciprocals of each other....therefore, ur lines are perpendicular <==
