Question

Given the quantities a = 8.9 m, b = 4.9 s, c = 71 m/s, what is the value of the quantity d = a3/(cb2)

Answer 1

The given expression is

$d = \frac{a^3}{c b^2}$

We have to find the value of d , given the values of a,b and c are 8.9m,4.9 s , 71m/s respectively .

To find the value of d, we have to substitute the given values of a,b and c, that is

$d = \frac{8.9^3}{71*4.9^2}$

$d = 0.4135$