Good points... just answer the question correctly

Mathematics

2 answers:

NeTakaya3 years ago

5 0

Answer:

R'(-9,4) --------------- R'(9,-4)

Step-by-step explanation:

Ivenika [448]3 years ago

3 0

9514 1404 393

Answer:

(a) R(-9, 4) ⇒ R'(9, -4)

Step-by-step explanation:

Reflection over the x-axis changes the sign of the y-coordinate only:

(x, y) ⇒ (x, -y) . . . . . . . reflection over the x-axis

When both signs are changed, the reflection is over the origin:

(x, y) ⇒ (-x, -y) . . . . . . reflection over the origin (or rotation 180°, or reflection over both axes)

All of the answer choices show one of these reflections. The first choice shows reflection over the origin, so the x-axis is not the line of reflection for ...

R(-9, 4) ⇒ R'(9, -4) . . . . . . origin is the point of reflection

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Which function has the domain x>-11

Marat540 [252]

<h2>Answer</h2>

$y=\sqrt{x+11} +5$

<h2>Explanation</h2>

Remember that the square root function is not defined, in the set of real numbers, for negatives values, so its radicand (the thing inside the square root) must be zero or bigger than zero. In other words, to find the domain of a square root function, you should set the thing inside the radical bigger or equal to zero and solve for x. Let's find the domain of each one of our functions:

For $y=\sqrt{x+11} +5$

The thing inside the square root is $x+11$ , so we are setting that bigger or equal than zero and solve for x to find the domain of the function: