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Kobotan [32]
3 years ago
5

Good points... just answer the question correctly​

Mathematics
2 answers:
NeTakaya3 years ago
5 0

Answer:

R'(-9,4)  --------------- R'(9,-4)

Step-by-step explanation:

Ivenika [448]3 years ago
3 0

9514 1404 393

Answer:

  (a)  R(-9, 4) ⇒ R'(9, -4)

Step-by-step explanation:

Reflection over the x-axis changes the sign of the y-coordinate only:

  (x, y) ⇒ (x, -y) . . . . . . . reflection over the x-axis

__

When both signs are changed, the reflection is over the origin:

  (x, y) ⇒ (-x, -y) . . . . . . reflection over the origin (or rotation 180°, or reflection over both axes)

__

All of the answer choices show one of these reflections. The first choice shows reflection over the origin, so the x-axis is not the line of reflection for ...

  R(-9, 4) ⇒ R'(9, -4) . . . . . . origin is the point of reflection

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One positive number is 5 times another number. The difference between the two numbers is 1464, find the numbers.
Brut [27]

Answer:

The answer is 292.8

Step-by-step explanation:

You just have to divided 1464 by 5

7 0
3 years ago
2(4x+2)=4x-12(x-1)<br> Solve the equation
kodGreya [7K]

Step-by-step explanation:

here you go hope it helps

7 0
2 years ago
6×_=44. six times what equals 44
BigorU [14]
The answer is 7.333, the threes are ongoing.

To find this answer you would just divide 44 and 6, since you are trying to find groups of the number stated.

Hope that helped.
8 0
4 years ago
HELP ASAP!!
GuDViN [60]

Step-by-step explanation:

Xm = (-3+3)/2 = 0/2 = 0

Ym = (2-2)/2 = 0/2 =0

so, the midpoint (Xm, Ym) is (0 , 0)

7 0
3 years ago
Read 2 more answers
NEED HELP Find values for a, b, c, and d so that the following matrix product equals the 2X2 identity matrix. Explain or show ho
ehidna [41]

We want to find the values of a, b, c, and d such that the given matrix product is equal to a 2x2 identity matrix. We will solve a system of equations to find:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

<h3>Presenting the equation:</h3>

Basically, we want to solve:

\left[\begin{array}{cc}-1&2\\a&1\end{array}\right]*\left[\begin{array}{cc}b&c\\1&d\end{array}\right] = \left[\begin{array}{cc}1&0\\0&1\end{array}\right]

The matrix product will be:

\left[\begin{array}{cc}-b + 2&-c + 2d\\a*b + 1&a*c + d\end{array}\right]

Then we must have:

-b + 2 = 1

This means that:

b = 2 - 1 = 1

  • b = 1

We also need to have:

a*b + 1 = 0

we know the value of b, so we just have:

a*1 + b = 0

  • a = -1

Now the two remaining equations are:

-c + 2d = 0

a*c + d = 1

Replacing the value of a we get:

-c + 2d = 0

-c + d = 1

Isolating c in the first equation we get:

c = 2d

Replacing that in the other equation we get:

-(2d) + d = 1

-d = 1

  • d = -1

Then:

c  = 2d = 2*(-1) = -2

  • c = -2

So the values are:

  • b = 1
  • a = -1
  • c = -2
  • d = -1

If you want to learn more about systems of equations, you can read:

brainly.com/question/13729904

4 0
3 years ago
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