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3 years ago

PLEASE HELP!!! MATH!!!

Mathematics

2 answers:

labwork [276]3 years ago

3 0

$-\frac{1}{2} = y -1\\y=0.5$

$-3\pi + w = 2\pi\\w= 5\pi$

$1.2m = 0.6\\m = 0.5$

$q + 2.7 + -0.9 = q + 1.8$

USPshnik [31]3 years ago

3 0

Answer:

Step-by-step explanation:

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Hiiiooo! Can someone please help ❤️

V125BC [204]

Answer:

B. √21

Step-by-step explanation:

x^2 = √5 x √5 + 4 x 4

x^2 = 5 + 16

x^2 = 21

x = √21

Hope that helps! :)

-Aphrodite

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3 years ago

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Can someone help me with problems J-L PLZZZ ITS URGENT DUE TOMORROW AND I REALLY NEED HELP AND IM SO TIRED

siniylev [52]

h. y / x^2

j. 0.00001

k. 0.000005

I. 0.025

m. 8 times 10^-3

n. 1.25 times 10^-4

o. 5 times 10^-7

p. 0.000000001

I only did the ones I see, hope it helps.

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3 years ago

The population, P(t), of China, in billions, can be approximated by1 P(t)=1.394(1.006)t, where t is the number of years since th

vitfil [10]

Answer:

At the start of 2014, the population was growing at 8.34 million people per year.

At the start of 2015, the population was growing at 8.39 million people per year.

Step-by-step explanation:

To find how fast was the population growing at the start of 2014 and at the start of 2015 we need to take the derivative of the function with respect to t.

The derivative shows by how much the function (the population, in this case) is changing when the variable you're deriving with respect to (time) increases one unit (one year).

We know that the population, P(t), of China, in billions, can be approximated by $P(t)=1.394(1.006)^t$

To find the derivative you need to:

$\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=\\\\\mathrm{Take\:the\:constant\:out}:\quad \left(a\cdot f\right)'=a\cdot f\:'\\\\1.394\frac{d}{dt}\left(1.006^t\right)\\\\\mathrm{Apply\:the\:derivative\:exponent\:rule}:\quad \frac{d}{dx}\left(a^x\right)=a^x\ln \left(a\right)\\\\1.394\cdot \:1.006^t\ln \left(1.006\right)\\\\\frac{d}{dt}\left(1.394\cdot \:1.006^t\right)=(1.394\cdot \ln \left(1.006\right))\cdot 1.006^t$

To find the population growing at the start of 2014 we say t = 0

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(0)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^0\\P(0)' = 0.00833901 \:Billion/year$

To find the population growing at the start of 2015 we say t = 1

$P(t)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^t\\P(1)' = (1.394\cdot \ln \left(1.006\right))\cdot 1.006^1\\P(1)' = 0.00838904 \:Billion/year$

To convert billion to million you multiple by 1000

$P(0)' = 0.00833901 \:Billion/year \cdot 1000 = 8.34 \:Million/year \\P(1)' = 0.00838904 \:Billion/year \cdot 1000 = 8.39 \:Million/year$

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3 years ago

Based on your observations from Question 1, what is the relationship between AE and BF when DFB and CEA measure something other

VMariaS [17]

Answer:

if angle dfb and angle cea measure something other than 90degrees, then line we is not equal to line bf. in this case, line and and line cd intersect at a single point.

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Use the unit circle to find the value of each trigonometric function at the angle indicated

Elan Coil [88]

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-1
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repectively

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3 years ago

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