Answer: a.This is the average number of days the house stayed on the market before being sold for $150,000.
Step-by-step explanation:
Given: f(p) be the average number of days a house stays on the market before being sold for price p in $1,000s.
To find the meaning f(150),
here p= 150 which means f(150) is the average number of days a house stays on the market before being sold for price 150 in $1,000s.
And 150 in $ 1,000= $150,000
Therefore, f(150) is the average number of days a house stays on the market before being sold for price $150,000.
Answer:
Answer is 910
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Step-by-step explanation:
Answer:
The correct answer is B.
Step-by-step explanation:
In order to find this, calculate out the discriminant for each of the following equations. If the discriminant is a perfect square, then it can be factored.
Discriminant = b^2 - 4ac
The only of the equations that does not yield a perfect square is B. The work for it is done below for you.
Discriminant = b^2 - 4ac
Discriminant = 7^2 - 4(2)(-5)
Discriminant = 49 + 40
Discriminant = 89
Since 89 is not a perfect square, we cannot factor this.
Answer: 195.5 or 12 7/32
Step-by-step explanation:
There is no letter tetha in the table so I use α instead. However it is not sence to final result.
The expression is:
(sinα+cosα)/(cosα*(1-cosα))
Lets divide the nominator and denominator by cosα
(sinα/cosα+cosα/cosα)/(cosα*(1-cosα)/cosα)= (tanα+1)/(1-cosα)=
=(8/15+1)/(1-cosα)= 23/(15*(1-cosα)) (1)
As known cos²α=1-sin²α (divide by cos²α both sides of equation)
cos²a/cos²α=1/cos²α-sin²α/cos²α
1=1/cos²α-tg²α
1/cos²α=1+tg²α
cos²α=1/(1+tg²α)
cosα=sqrt(1/(1+tg²α))= +-sqrt(1/(1+64/225))=+-sqrt(225/(225+64))=
=+-sqrt(225/289)=+-15/17 (2)
Substitute in (1) cosα by (2):
1st use cosα=15/17
1) 23/(15*(1-cosα)) =23/(15*(1-15/17))= 23*17/2=195.5
2-nd use cosα=-15/17
2)23/(15*(1-cosα)) =23/(15*(1+15/17))= 23*17/32=12 7/32
