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MissTica
3 years ago
7

50 Points for the full answer to this question!!!

Mathematics
2 answers:
Evgen [1.6K]3 years ago
8 0

a, b, c) see the attachment

d) y = -34.4762(x -2.44268)² +281.613

Explanation:

Using Desmos is pretty straightforward for doing what the problem statement asks. You make a table, then write an equation for y₁ in terms of x₁ using the tilde (~) for the equal sign. Desmos chooses values of the coefficients to make the curve of best fit and lists those for you.

For part (b) of your question, you will have to copy the values into the form of the equation: replace "a" with its value, "b" with its value, "c" with its value.

The vertex point has been highlighted on the curve, so you can read its coordinates on the graph.

_____

The equation you write relating x₁ and y₁ can be written in vertex form, so you can have Desmos tell you the appropriate numbers directly. (See the second attachment.) As it works out, you don't have to, because the "a" value and the vertex coordinates are all you need to write the equation in vertex form.

soldier1979 [14.2K]3 years ago
5 0
<h3>Answer:</h3>

a, b, c) see the attachment

d) y = -34.4762(x -2.44268)² +281.613

<h3>Explanation:</h3>

Using Desmos is pretty straightforward for doing what the problem statement asks. You make a table, then write an equation for y₁ in terms of x₁ using the tilde (~) for the equal sign. Desmos chooses values of the coefficients to make the curve of best fit and lists those for you.

For part (b) of your question, you will have to copy the values into the form of the equation: replace "a" with its value, "b" with its value, "c" with its value.

The vertex point has been highlighted on the curve, so you can read its coordinates on the graph.

_____

The equation you write relating x₁ and y₁ can be written in vertex form, so you can have Desmos tell you the appropriate numbers directly. (See the second attachment.) As it works out, you don't have to, because the "a" value and the vertex coordinates are all you need to write the equation in vertex form.

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Z^m-n (z^m+ z^m+n + z^n)
rusak2 [61]

Answer:Your left hand side evaluates to:

m+(−1)mn+(−1)m+(−1)mnp

and your right hand side evaluates to:

m+(−1)mn+(−1)m+np

After eliminating the common terms:

m+(−1)mn from both sides, we are left with showing:

(−1)m+(−1)mnp=(−1)m+np

If p=0, both sides are clearly equal, so assume p≠0, and we can (by cancellation) simply prove:

(−1)(−1)mn=(−1)n.

It should be clear that if m is even, we have equality (both sides are (−1)n), so we are down to the case where m is odd. In this case:

(−1)(−1)mn=(−1)−n=1(−1)n

Multiplying both sides by (−1)n then yields:

1=(−1)2n=[(−1)n]2 which is always true, no matter what n is

8 0
3 years ago
ILL BRAINLIEST YOU PLEASE HELP ME
gtnhenbr [62]

Answer:

Option C

The length of RT is 14

Step-by-step explanation:

For a given Right Triangle

m∠R = 90°, RG = 17, TG = 22

Now, <u>By Pythagoras Theorem</u>

(RT)² + (RG)² = (TG)²

(RT)² = (TG)² - (RG)²

(RT)² = (22)² - (17)²

(RT)² = 484 - 289

(RT)² = 195

RT = √195

RT = √195 = 13.96 = 14

Thus, The length of RT is 14

<u>-TheUnknownScientist</u>

4 0
3 years ago
A man flies a kite at a height of 15 ft. The wind is carrying the kite horizontally from the man at a rate of 5 ft./s. How fast
Misha Larkins [42]

Answer:

4.4 ft/s

Step-by-step explanation:

Height = 15ft

Rate= 5 ft/s

Distance from the man to the kite= 32ft

dh/dt = 5 ft/s

h = √32^2 - 15^2

h = √ 1025 - 225

h = √800

h = 28.28ft

D = √15^2 + h^2

dD/dt = 1/2(15^2 + h^2)^-1/2 (2h) dh/dt

= h(225 + h^2)^-1/2 dh/dt

= (h / √225 + h^2)5

= (28.28 / √225 + 28.28^2)5

= (28.28 / √1024.7584)5

= (28.28/32)5

= 0.88*5

= 4.4 ft/s

3 0
3 years ago
Convert 150 meters per second into miles per day
statuscvo [17]
 just divide it is simple bruh
3 0
3 years ago
Solve the system of equations y=9x+13 y=2x+48
MakcuM [25]
Both are equal y. So you can set them equal to each other

9x+13=2x+48

Subtract 2x from both sides

7x+13=48
Subtract 13 from both sides

7x= 35

X=5
7 0
3 years ago
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