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3 years ago

The quotient of 1.2 added to a number and 5 is 3.6?

Mathematics

2 answers:

Margaret [11]3 years ago

7 0

You would add 5 and 1.2 which gives you 6.2 and you add negative 3.6 then it gives you 3.6.

Nat2105 [25]3 years ago

5 0

You would add 5 and 1.2 which gives you 6.2 then you add negative 3.6 which then gives you 3.6.

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How do you use the vertical line test?

Triss [41]

First let you know what to do. OK. Going to drag a ruler. Across the paper. Vertically. And if it touches 2 points on the grid. Then it fails the test.

5 0

3 years ago

Which of the following is true?

Ratling [72]

In this question, we're trying to find the inequality that is true.

To find your answer, we can convert the numbers in the absolute value:

|−5| < 4:

5 < 4 false

|−4| < |−5|:

4 < 5 true

|−5| < |4|

5 < 4 false

|−4| < −5

4 < -5 false

The only true inequality here would be |−4| < |−5|, since it works with the inequality sign.

Answer:

|−4| < |−5|

4 0

3 years ago

You have 3/4 of a pound of peanuts. You have 10 cupcakes . What fraction of nuts is in each cupcake

kvasek [131]

Each cupcake would have 3/40 of a pound of nuts since that is 10x smaller than the total they have so they could put that amount into 10 cupcakes.

The answer is 3/40

8 0

3 years ago

Is 4y=16x a Direct variation

gizmo_the_mogwai [7]

In the given equation, as the value of y increase, the value of x also

increases.

Yes, 4·y = 16·x is a direct variation

Reasons:

A direct variation is a relationship that exists between two variables. It is

also known as a direct proportion which can be expressed as; y = k·x

Where k is a number

The given equation is 4·y = 16·x

Dividing both sides by 4 gives;

$\displaystyle \frac{4 \cdot y}{4} = \frac{16 \cdot x}{4} = \frac{4 \times 4 \cdot x}{4}$

Which gives;

y = 4·x

Comparing the above equation with the equation for a direct variation gives;

y = 4·x

y = k·x

Therefore;

k = 4

The equation, y = 4·x, and therefore, the equation from which it is derived, 4·y = 16·x, is a direct variation.

Learn more about direct variation here:

brainly.com/question/6499629

6 0

2 years ago

What are the possible values of x for the following functions?

stiks02 [169]

What can a denominator never be?

0

so, we need to figure what x can't be... the only way to multiply 2 things together to get 0 is if one or both are zero.

so, what x values make our denominator 0?

to figure this out, we need to set (x-1)(x-2)=0

now we split and solve.

$x - 1 = 0 \\ x - 2 = 0$
so when x is 1 or 2 the function doesnt make sense.

but, x can be every other number and it does, so the answer is
ALL REAL NUMBERS not equal to 1 or 2

7 0

3 years ago