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3 years ago

WHAT IS THE NAME YOU OF A SOLID THAT HAS TWO PARRALLEL POLYGON BASES AND ALL OTHER FACES THAT ARE RECTANGLES 2 SEE ANSWERS

Mathematics

2 answers:

Inessa [10]3 years ago

8 0

Anwser:

Prism (whatever shape the base is you put before prism)

TEA [102]3 years ago

5 0

<h2>Question:</h2><h3>WHAT IS THE NAME YOU OF A SOLID THAT HAS TWO PARRALLEL POLYGON BASES AND ALL OTHER FACES THAT ARE RECTANGLES 2 SEE ANSWERS?</h3>

Step-by-step explanation:

<h3>A prism is a three-dimensional figure with two</h3>

<h3> parallel, congruent bases. The bases, which are</h3>

<h3> also two of the faces, can be any polygon. The </h3>

<h3>other faces are rectangles. A prism is named </h3>

<h3>according to the shape of its bases.</h3>

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the rectangular grassy plot 126 m by 48m has a gravel path 1.5m wide a road 2.5m wide is constructed all around it on inside of

dusya [7]

Answer:

= Sh. 2281.50

Step-by-step explanation:

Area of the path;

(126 × 2.5 ) + (2.5 × (48 - (2.5×2)

= 315 + (2.5 × 43)

= 315 + 107.5

= 422.5 m²

But; the cost of graveling is sh 5.40 per square meter

Therefore; The cost of graveling the whole path;

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3 years ago

What do you know to be true about the values of p and q.

Jobisdone [24]

Answer:

A. p = q

Step-by-step explanation:

For each triangle, add the angles together and then subtract the sum from 180°.

First triangle:

60° + 50° = 110°

180° - 110° = 70°

Missing angle = 70°

Second triangle:

80° + 30° = 110°

180° - 110° = 70°

Missing angle = 70°

Hope this helps :)

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2 years ago

What is the answer to |4r−12| , if r<3?

Sav [38]

Answer:

Step-by-step explanation:

|4r−12| = -(4r-12) when 4r-12< 0

4r< 12 so r<3

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3 years ago

Without using logarithm tables, find the value of x given that: 2log2/3 = 1/2logx - log 18 + log 16

sweet-ann [11.9K]

Answer:

$x=\frac{1}{4}$

Step-by-step explanation:

<u>Given:</u>

$2log(\frac{2}{3})=\frac{1}{2}log(x)-log(18)+log(16)$

<u>Use the Power Rule Law:</u>

$log(\frac{2}{3}^2)=log(x^{1/2})+log(16)-log(18)$

<u>Use the Quotient Rule Law:</u>

$log(\frac{4}{9})=log(\sqrt{x})+log(\frac{16}{18})$

<u>Use the Product Rule Law:</u>

$log(\frac{4}{9})=log(\frac{16\sqrt{x}}{18})$

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$log(\frac{4}{9})=log(\frac{8\sqrt{x}}{9})$

$\frac{4}{9}=\frac{8\sqrt{x}}{9}$

$4=8\sqrt{x}$

$\frac{4}{8}=\sqrt{x}$

$\frac{1}{2}=\sqrt{x}$

$\frac{1}{4}=x$

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1 year ago

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Tom [10]

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2 years ago