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ohaa [14]
2 years ago
10

A club swimming pool is 21ft wide and 41ft long. The club members want a uniform width border around the pool. They have enough

material for 264 ft squared. How wide can the strip be?

Mathematics
1 answer:
oksano4ka [1.4K]2 years ago
4 0

<u>Answer-</u>

<em>Strip with </em><em>2.13 ft </em><em>width can be used. </em>

<u>Solution-</u>

A club swimming pool is 21 ft wide and 41 ft long.

Hence, the perimeter of the swimming pool is

P=2(\text{Length}+\text{Width})=2(41+21)=2(62)=124\ ft

The club members want a uniform width border around the pool.

They have enough material for 264 ft²

As they will cover the perimeter of the rectangular pool, so the length of the total used strip is equal to the perimeter of the swimming pool.

Let the width of the strip is x ft

So, the total area of the used strip is,

A=\text{Length}\times \text{Width}

Putting the values,

\Rightarrow 264=124\times x

\Rightarrow x=\dfrac{264}{124}

\Rightarrow x=2.13\ ft

Therefore, strip with 2.13 ft width can be used.

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A 46 gram sample of a substance that is used to sterilize surgical instruments has a k-value of 0.1374. Find the substance's hal
mars1129 [50]

Answer:

  t=5.0days

Step-by-step explanation:

Using the formula for the exponential decay that is N=N_{0}e^{-kt}, we have N=\frac{1}{2}{\times}46=23, N_{0}=46 and k=0.1374.

Thus, N=N_{0}e^{-kt} becomes

23=46{\times}e^{-0.1374t}

\frac{23}{46}=e^{-0.1374t}

\frac{1}{2}=e^{-0.1374t}

Taking log on both sides, we get

ln(\frac{1}{2})={-0.1374t}

t=\frac{ln\frac{1}{2}}{-0.1}

t=\frac{-0.6931}{-0.1374}

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4 0
2 years ago
Given that WA = 5x – 8 and WC = 3x + 2, find WB. A. WB = 5 B. WB = 8 C. WB = 10 D. WB = 17
rodikova [14]
The rest of the question is the attached figure.
============================================
Δ AYW a right triangle at Y ⇒⇒⇒ ∴ WA² = AY² + YW²
And AY = YB ⇒⇒⇒ ∴ WA² = YB² + YW²   → (1)
Δ BYW a right triangle at Y ⇒⇒⇒ ∴ WB² = BY² + YW²  → (2)
From (1) , (2)  ⇒⇒⇒ ∴ WA = WB  →→ (3)
Δ CXW a right triangle at Y ⇒⇒⇒ ∴ WC² = CX² + XW²
And CX = XB ⇒⇒⇒ ∴ WC² = XB² + XW²   → (4)
Δ BXW a right triangle at Y ⇒⇒⇒ ∴ WB² = XB² + XW²  → (5)
From (4) , (5)  ⇒⇒⇒ ∴ WC = WB  →→ (6)
From (3) , (6)
WA = WB = WC
given ⇒⇒⇒ WA = 5x – 8 and WC = 3x + 2
∴ <span> 5x – 8 = 3x + 2</span>
Solve for x ⇒⇒⇒ ∴ x = 5
∴ WB = WA = WC = 3*5 + 2 = 17

The correct answer is option D. WB = 17






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3 years ago
Please help. A rectangle's length and width are in a ratio of 7:3. The area is 84 square feet. What are the
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Answer:

length = 14 feet

width = 6 feet

Step-by-step explanation:

A = 84 feet square

ratio of length and width = 7 : 3

total ratio of length and width 10 = a

length = (7/10)a

width = (3/10)a

A = length x width = (7/10)a x (3/10)a = (21/100)a² = 84

a² = 84 x 100 : 21 = 400

a = 20 feet

length = 7/10 x 20 = 14 feet

width = 3/10 x 20 = 6 feet

8 0
2 years ago
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