Answer:
ifk
Step-by-step explanation:
Area of rectangle= base x height
6x4=24
Area of triangle= 0.5 base x height
We have the height but we don’t have the base, to calculate the base we subtract 10-6 which equals to 4
0.5 x 4 x4 =8
Area of a semicircle= o.5 x pi x r^2
We have the diameter and to find the radius we divide it by 2
4/2 = 2
0.5 x pi(or 3.14) x 2^2
=6.28
Total area = 24 + 8+ 6.28 =38.28cm^2
Answer:
x = 1 or x = -5
Step-by-step explanation:
We are given;
- The quadratic equation, x² + 4x - 13 = -8
We are required to solve the equation using the completing square method.
To do this, we use the following steps;
Step 1: We make sure the coefficient of x² is one
x² + 4x - 13 = -8
Step 2: Combine the like terms (take the constant term to the other side)
x² + 4x - 13 = -8
x² + 4x = -8 + 13
we get
x² + 4x = 5
Step 3: We add the square of half the coefficient of x on both sides of the equation
Coefficient of x = 4
Half of coefficient of x = 2
Square of half the coefficient of x = 2² (4)
We get;
x² + 4x + (2²) = 5 + (2²)
Step 4: Put x and 2 under one square and the solve the other side of the equation.
We get
(x + 2)² = 5 + 4
(x + 2)² = 9
Step 5: Get the square root on both sides of the equation;
(x + 2)² = 9
√(x + 2)² = ±√9
(x + 2)= ±3
Therefore;
x+2 = + 3 or x + 2 = -3
Thus, x = 1 or -5
The solution of the equation is x = 1 or x = -5
Answer:

Step-by-step explanation:
just replace x by 2
Using the volume of the spherical balloon, it is found that it will take 24 hours for the balloon to become completely empty.
<h3>What is the volume of a sphere?</h3>
The volume of a sphere of radius r is given by:

Aspherical balloon has a radius of 6 feet, hence the volume is:

It has already lost 20% of it's air, and air is leaking out of the balloon at a rate of 30 cubic feet per minute, hence the volume after t minutes is given by:


It will be completely empty when:





Rounding, it will take 24 hours for the balloon to become completely empty.
More can be learned about the volume of a sphere at brainly.com/question/25608353