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Dahasolnce [82]
3 years ago
11

he transport layer on the destination host O reassembles the application message if it has been fragmented O removes the transpo

rt header O both A and B O neither A nor B
Computers and Technology
1 answer:
Dafna1 [17]3 years ago
4 0

Answer: Both A and B

Explanation: Transport layer is the level of the OSI model which is helpful in maintaining the overall network communication.The application process that is being executed in the layers of architecture gets logical communication through transport layer.

It has the ability to connect the data that has been divided into section for the transportation.It can also act on the transport header ,which finds the transmission flow of specific data when not required.

You might be interested in
Create and Provide complete program that includes a comments header with your name, course, section and other program details an
agasfer [191]

Answer:

Written using C++

/*Enter Your Details Here*/

#include<iostream>

#include<cmath>

using namespace std;

int main()

{

//1

float side;

cout<<"Enter the side of a square: ";

//2

cin>>side;

//3

float perimeter = 4 * side;

cout<<"The perimeter is "<<perimeter<<endl;

//4

float area = side *side;

cout<<"The area is "<<area<<endl;

//5

float diagonal = sqrt(2 * side * side);

cout<<"The length of the diagonal is "<<diagonal;

return 0;

}

Explanation:

<em>I've added the full source code as an attachment where I used more comments to </em><em>explain </em><em>difficult line</em>

Download cpp
7 0
3 years ago
What is not true of efs
Lemur [1.5K]

Answer:

EFS cannot store files encrypted.

Explanation:

EFS) is a feature introduced in version 3.0 of NTFS that provides filesystem-level encryption. EFS is useful for mobile computer users, whose computer are subject to physical theft, and for storing highly sensitive data. Encryption itself is the method where the information is converted into secret code that hides the information's true meaning. (EFS) is used to encrypt files and folders. EFS is easy to use, with nothing more than a check box in a file’s properties. It is not fully supported on Windows 7 Starter, Windows 7 Home Basic, and Windows 7 Home Premium!

3 0
3 years ago
What is a document?read.Miércoles, 19 de agosto ¡Saludos Mario! ¿Cómo estás amigo? ¿Cómo está tu familia en Caracas? Mi familia
natka813 [3]

Answer:

A Document is a virtual paper that you can type on

Explanation:

A piece of written or electronic paper that provides information or evidence or that serves as an record.

7 0
2 years ago
Illustrate that the system is in a safe state by demonstrating an order in which the threads may complete.If a request from thre
Kamila [148]

Answer:

a. safe sequence is T2 , T3, T0, T1, T4.

b. As request(T4) = Available, so the request can be granted immediately

c. As request(T2) < Available, so the request can be granted immediately

d. As request(T3) < Available, so the request can be granted immediately.

Explanation:

It will require matrix

[i, j] = Max [i, j] – Allocation [i, j]

A B C D

T0 3 3 3 2

T1 2 1 3 0

T2 0 1 2 0

T3 2 2 2 2

T4 3 4 5 4

Available = (2 2 2 4)

1. Need(T2) < Available so, T2 can take all resources

Available = (2 2 2 4) + (2 4 1 3) (Allocation of T2) = (4 6 3 7)

2. Need(T3)<Available so, T3 will go next

Available = (4 6 3 7) + (4 1 1 0) = (8 7 4 7)

Like wise next T0, T1, T4 will get resources.

So safe sequence is T2 , T3, T0, T1, T4.

(Note, there may be more than one safe sequence).

Solution b.

Request from T4 is (2 2 2 4) and Available is (2 2 2 4)

As request(T4) = Available, so the request can be granted immediately.

Solution c.

Request from T2 is (0 1 1 0) and Available is (2 2 2 4)

As request(T2) < Available, so the request can be granted immediately.

Solution d.

Request from T3 is (2 2 1 2) and Available is (2 2 2 4)

As request(T3) < Available, so the request can be granted immediately.

5 0
3 years ago
Write a function with two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The func
Allisa [31]

Answer:

Here is the program:

#include <iostream>  //to use input output functions

#include <string>  // to use functions to manipulate strings

using namespace std;  //to identify objects cin cout

void function(string prefix, unsigned int levels){  // function that takes two parameters, a string, using the string class and levels an unsigned integer

   if (levels == 0) {  //if number of levels is equal to 0

       cout << prefix << endl;  //displays the value of prefix

       return;    }  

  for (int i = 1; i <=9 ; i++){  //iterates 1 through 9 times

       string sections = (levels == 1 ? "" : ".");  //if the number of levels is equal to 1 then empty space in sections variable otherwise stores a dot

       string output = prefix +  std::to_string(i) + sections;   // displays the string prefix followed by the section numbers. Here to_string is used to convert integer to string

       function(output, levels - 1);   } }   //calls function by passing the resultant string and levels-1  recursively to print the string prefix followed by section numbers

int main() {  // start of main function

   int level = 2;  //determines the number of levels

   function("BOX", level);  } //calls function by passing the string prefix and level value

Explanation:

The program has a function named function() that takes two parameters, prefix (a string, using the string class from ) and levels (an unsigned integer). The function prints the string prefix followed by "section numbers" of the form 1.1., 1.2., 1.3., and so on. The levels argument determines how many levels the section numbers have. If the value of levels is 0 means there is 0 level then the value of prefix is printed. The for loop iterates '1' through '9' times for number of digits in each level. If the number of levels is 1 then space is printed otherwise a dot is printed. The function() calls itself recursively to print the prefix string followed by section numbers.

Let us suppose that prefix = "BOX" and level = 1

If level = 1 then the loop for (int i = 1; i <=9 ; i++) works as follows:

At first iteration:

i = 1

i <=9 is true because value of i is 1

string sections = (levels == 1 ? "" : "."); this statement checks if the levels is equal to 1. It is true so empty space is stored in sections variable so,

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement has prefix i.e BOX plus value of i which is 1 and this int value is converted to string by to_string() method plus sections has an empty space. So this statement becomes

string output = BOX + 1  

So this concatenates BOX with 1 hence output becomes:

output = BOX1

At second iteration:

i = 2

i <=9 is true because value of i is 2

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 2  

So this concatenates BOX with 1 hence output becomes:

output = BOX2

At third iteration:

i = 3

i <=9 is true because value of i is 3

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 3  

So this concatenates BOX with 1 hence output becomes:

output = BOX3

Now at each iteration the prefix string BOX is concatenated and printed along with the value of i. So at last iteration:

At last iteration:

i = 9

i ==9 is true because value of i is 9

string sections = (levels == 1 ? "" : "."); is true so

sections = ""

Next, string output = prefix +  std::to_string(i) + sections; statement becomes

string output = BOX + 9  

So this concatenates BOX with 1 hence output becomes:

output = BOX9

After this the loop breaks at i = 10 because the condition i<=9 becomes false. So the output of the entire program is:

BOX1                                                                                                                                          BOX2                                                                                                                                          BOX3                                                                                                                                          BOX4                                                                                                                                          BOX5                                                                                                                                          BOX6                                                                                                                                          BOX7                                                                                                                                          BOX8                                                                                                                                          BOX9  

The program along with the output is attached.

4 0
3 years ago
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