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jeyben [28]
3 years ago
15

Artists who draw images on a computer often use a stylus in conjunction with special _________ tablets, which offer extra-sensit

ive touch surfaces that translate an artist's motions into drawings on the computer screen.
Computers and Technology
1 answer:
hodyreva [135]3 years ago
6 0

Answer:

Graphics is the correct answer to the following question.

Explanation:

The following answer is true because Graphic tablet is the device in which a person can draw graphics, images or they can also draw by their hands with use of digital pen which is use for drawing as they draw images on the paper. we can also say the graphic tablet is used for the digital art.

So, That's why the following answer is correct.

You might be interested in
Write an if-else statement to describe an object. Print "Balloon" if isBalloon is true and isRed is false. Print "Red balloon" i
Marat540 [252]

Answer:

if(isBalloon== true && isRed==false) //compare the value of isBalloon variable with true value and isRed variable value with false value.

   System.out.println("Balloon");//Print Balloon

else if(isBalloon== true && isRed==true) //compare the value of isBalloon variable with true value and isRed variable value with also true value.

System.out.println("Red balloon");//Print Red  Balloon

else // when no if condition match it will execute.

System.out.println("Not a balloon"); //Print Not a Balloon

Output:

Not a balloon

Explanation:

The "if-else" statement is defined above for the problem which is given on the question. The detailed explanation of the answer is described below--

  • Firstly we need to check the "true" value for the "isBalloon" variable and "false" value for "isRed" variable. This is done in "if" statement separated with and(&&) operator which gives "true" when both are the true statement.
  • Then we need to check the "true" value for the "isBalloon" variable and "isRed" variable. For this, we need to use "else if" statement which executes when "if" statement is false.
  • Then we need to print the "Not a balloon" statement if both cases are false, for this, we use "else" statement which executes when the "if" and "else if" statement are false.

6 0
4 years ago
The right headlight does not function on either high or low beam. Technician A says this could be caused by an open ground on th
dangina [55]

Answer: Technician A is correct.

Explanation: An open ground on the right may be the reason the headlight is not functioning on low or high beam. Most electrical circuit related problems in automotive are caused by open ground.

A ground should be clean, tight and free of corrosion and also making good metal to metal contact.

A ground is an electrical circuit system or connection in an automotive.

A dimmer switch on the other hand is a device that controls the vehicle's headlight functions. If the headlight does not function on high or low on the right. It can't be a dimmer switch, hence it may be ground problem.

4 0
3 years ago
Python Coding:
leva [86]

Answer:

# Here we are asking the user for a number two times

userInput1 = input("Enter any #: ")

userInput2 = input("Enter any # again: ")

# We compare if userInput1 is greater than userInput2

if(userInput1 > userInput2):

   # Print userInput1 if userInput1 is greather than userInput2

   print("First Number: " + userInput1)

   # Otherwise, print userInput2

else:

   print("Second Number: " + userInput2)

# Initiate a while-loop

while(True):

   # The lines below are from above

   userInput1 = input("\nEnter any #: ")

   userInput2 = input("Enter any # again: ")    

   if(userInput1 > userInput2):

       print("First Number: " + userInput1)

   else:

       print("Second Number: " + userInput2)

   # We ask the user whether they would like to stop

   stop = input("\nWould you like to stop? (Yes or No)")

   # Compare the String stop with "Yes"

   if(stop == "Yes"):

       # If true then break

       break

Explanation:

The use of \n is unnecesary, but it skips a line and provides more readability.

5 0
2 years ago
What does Adsl stand for?
spin [16.1K]
ADSL stands for Asymmetric Digital Subscriber Line


7 0
3 years ago
Read 2 more answers
Create a program in c/c++ which accepts user input of a decimal number in the range of 1 -100. Each binary bit of this number wi
kirill115 [55]

Answer:

// here is code in C++.

#include <bits/stdc++.h>

using namespace std;

void switch_fun(int input)

{

//array to store binary of input number

   int bin[7];

   // convert the number into binary

   for(int i=0; input>0; i++)

       {

           bin[i]=input%2;

           input= input/2;

       }

   // print the switch number and their status

   cout<<"Switch number:\t 1\t 2\t 3\t 4\t 5\t 6\t 7 \n";

   cout<<"status:      ";

   for(int j=6;j>=0;j--)

   {

   // if bit is 1 print "ON" else print "OFF"

       if(bin[j]==1)

           cout<<"\t ON";

       else

           cout<<"\t OFF";

   }

}

int main()

{

   int n;

   cout<<"enter the number between 1-100 only:");

   // read a number in decimal

   cin>>n

   // validate the input

   while(n<1 ||n>100)

   {

     cout<<"wrong input!! Input must be in between 1-100:"<<endl;

     cout<<"enter the number again :";

     cin>>n;

   }

// call the function with input parameter

  switch_fun(n);

return 0;

}

Explanation:

Read a decimal number from user. If the number is not between 1 to 100 the it will again ask user to enter the number until the input is in between 1-100.Then it will call the fun() with parameter n. First it will convert the decimal to binary array of size 7.Then print the status of switch.If bit is 1 then print "ON" else it will print "OFF".

Output:

enter the number between 1-100 only:-5

wrong input!! Input must be in between 1-100:

enter the number again :125

wrong input!! Input must be in between 1-100:

enter the number again :45

Switch number:   1       2       3       4       5       6       7

Status:          OFF     ON      OFF     ON      ON      OFF     ON

8 0
3 years ago
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