Answer:
(c)-All results for the experimental groups involving wing surgery would be invalid.
Explanation:
The study researcher shown in the above question noted that flies that underwent wing surgery were more attacked than those that received no wing treatment. However, the researcher does not show the study variables and, consequently, does not show any relationship between the variables and the research result. For this reason, we can state that based on this result, all results for experimental groups involving wing surgery would be invalid.
Answer:
2% of the progeny will be double crossovers for the trihybrid test cross
Explanation:
By knowing the positions of genes, we can estimate the distances in MU between them per region.
- Genes A and B are 10 map units apart (Region I)
- Genes B and C are 20 map units apart (Region II)
- Genes A and C are 30 map units apart
----A-------10MU--------B-------------20MU-------------C---
Region I Region II
We can estimate the recombination frequencies by dividing each distance by 100.
• recombination frequency of A-B region = 10MU / 100 = 0.10
• recombination frequency of B-C region = 20MU / 100 = 0.20
Now that we know the recombination frequencies in each region, we can calculate the expected double recombinant frequency, EDRF, like this:
EDRF = recombination frequency in region I x recombination frequency in region II.
EDRF = 0.10 x 0.20 = 0.02
2% of the progeny will be double crossovers for the trihybrid test cross
<span>Only a single amino acid could change, because the reading frame is unaffected</span>
the mitochondria breaks down chemical fuel into packets of chemical energy that can power the cell
