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Natali5045456 [20]
3 years ago
14

Consider the following piecewise-defined function.

Mathematics
2 answers:
Nitella [24]3 years ago
8 0

Answer:

Answer is 11

Step-by-step explanation:

Given in a piecewise function as

f(x) = x^2-5, x3

We find that the above function is defined for all real values of x except at x =3

We are to find out f(-4)

Since -4 we substitute -4 in the first function

f(-4) = (-4)^2-5= 11

Thus we get answer as 11

Fittoniya [83]3 years ago
7 0
In order to solve this, we need to select the function that meets our constraints. Since x^2 - 5 occurs when x is less than 3, and the x-value we are given is -4, we use the first function.

f(-4) = (-4)^2 - 5
f(-4) = 16 - 5
f(-4) = 11
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3 years ago
The sum of -3 and 12 increased by 5
aev [14]
-3+12+5=
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4 0
3 years ago
Read 2 more answers
How to get the answer
Aleonysh [2.5K]
So this is just working with exponents, but negative exponents can be a little tricky. your example didn't do a great job of showing how you calculate negative exponents.

for #2, you have 10⁻⁶

to convert negative exponents into something that makes more sense to our brain, you can set it beneath 1:

\frac{1}{10^6}  ... or, in the event that you can't see that because you're on the app: (1)/(10⁶). so now, instead of calculating 10⁻⁶, which would probably give you a confusing decimal, you just need to figure out 10⁶ -- and positive exponents are much easier to deal with.

10⁶ = 1,000,000
BUT remember that you have to put this value beneath a 1 to account for your negative exponent and (1/1,000,000) is your answer for part A.

so, use the same steps for the rest of the problems:
1) convert negative exponent to positive exponent beneath 1
7⁻³ = (1)/(7³)
2) calculate 7³
7³ = 343
<span>3) your result is (1/343)
</span>
<span>for 12</span>⁻², again, you'll put it beneath 1 so that it becomes (1)/(12²), then you'll calculate 12² (12*12 = 144), so that your result is (1/144). that leaves the letter D for number 2, which you'll have to write into your boxes at the top.

i hope this helps! you can message me if you have any specific ones that cause you trouble and i'll do my best to help.
5 0
4 years ago
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