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krek1111 [17]
3 years ago
15

Write five names for 64 .

Mathematics
2 answers:
user100 [1]3 years ago
5 0

For this case we have the following number:

64

We can rewrite the number in 5 different ways:


way 1:

In the form of a word:

64 = sixty-four


Way 2:

As the product of two numbers:

64 = two times thirty-two


Way 3:

As the division of two numbers:

64 = one hundred twenty-eight between 2.


Way 4:

As the sum of two numbers:

64 = sixty plus four


Way 5:

As the subtraction of two numbers:

64 = seventy minus six.

Natali [406]3 years ago
4 0
In word form: Sixty four
in expanded form: 6x10 + 4x1
in place value form: 6 tens + 4 ones
in Roman numeral form: LXIV
in Arabic numeral form: ٦٤
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What’s the probability of getting each card out of a deck?
VMariaS [17]

Answer:

a. 1/13

b. 1/52

c. 2/13

d. 1/2

e. 15/26

f. 17/52

g. 1/2

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a. In a deck of cards, there are 4 suits and each of them has a 7. Therefore, the probability of drawing a 7 is:

P(7) = 4/52 = 1/13

b. There is only one 6 of clubs, therefore, the probability of drawing a 6 of clubs is:

P(6 of clubs) = 1/52

c. There 4 fives (one for each suit) and 4 queens in a deck of cards. Therefore, the probability of drawing a five or a queen​​​​​​​​​​​ is:

P(5 or Q) = P(5) + P(Q)

= 4/52 + 4/52

= 1/13 + 1/13

P(5 or Q) = 2/13

d. There are 2 suits that are black. Each suit has 13 cards. Therefore, there are 26 black cards. The probability of drawing a black card is:

P(B) = 26/52 = 1/2

e. There are 2 suits that are red. Each suit has 13 cards. Therefore, there are 26 red cards. There are 4 jacks. Therefore:

P(R or J) = P(R) + P(J)

= 26/52 + 4/52

= 30/52

P(R or J) = 15/26

f. There are 13 cards in clubs suit and there are 4 aces, therefore:

P(C or A) = P(C) + P(A)

= 13/52 + 4/52

P(C or A) = 17/52

g. There are 13 cards in the diamonds suit and there are 13 in the spades suit, therefore:

P(D or S) = P(D) + P(S)

= 13/52 + 13/52

= 26/52

P(D or S) = 1/2

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3 years ago
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