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svetoff [14.1K]
3 years ago
14

Tyson multiplies 75 by 1.15. Which number might Tyson be trying to find?

Mathematics
2 answers:
Alchen [17]3 years ago
8 0

Answer:

A

Step-by-step explanation:

it is A because if you take 1.15 and move the decimals two places right it makes 115.

dolphi86 [110]3 years ago
7 0

Answer:

A

Step-by-step explanation:

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Help with my homework. Please.
garik1379 [7]

Answer:

Step-by-step explanation: since average speed = total distance/time

a)average speed of the journey from my home town to A = 10 miles/20 minutes = 0.5

b)journey from my home town to B = 20 miles/30 minutes = 0.7

c)10 miles + 20 miles = 30 miles

which takes 50 minutes

so: 30 miles/50 minutes = 0.6

5 0
3 years ago
120 times 1.75 show your work plz help me I really dont get it
sineoko [7]
120 * 1.75 = 200

5 times 0 = 0

5 times 2 = 10 carry the 1

5 times 1 = 5 + 1 = 6

7 times 0 = 0

7 times 2 = 14 carry the 1...

7 times 1 = 7 + 1 = 8
1 times 0 = 0
1 times 2 = 2
1 times 1 = 1
add it all together and you get 200.
6 0
3 years ago
The lines shown below are perpendicular.
elena-14-01-66 [18.8K]
The answer is True. In geometry, perpendicular lines are defined as two lines that meet or intersect each other at right angles (90°).
4 0
2 years ago
Read 2 more answers
Which is the equation of a circle whose center is at the origin and that passes through the point (3, 5)?
xxTIMURxx [149]

Answer:

x² + y² = 34

Formula:

  • (x - h)² + (y - k)² = r²                    where (h, k) is the center

<u>Here find the radius using distance formula</u>:                → origin : (0, 0)

  • √(x2-x1)²+(y2-y1)²
  • √(3-0)²+(5-0)²
  • √9+25
  • √34

<u>Thus the equation of circle</u>:

  • (x - 0)² + (y - 0)² = (√34)²
  • (x - 0)² + (y - 0)² = 34
  • x² + y² = 34

7 0
3 years ago
Read 2 more answers
And isosceles right triangle has two legs that are the same length and hypotenuse of 10 inches. Find the dimension of the leg.
amid [387]
Special Triangles Theorem
leg1=leg2=a
hypotenuse=a√2=10
Both Legs are 5√2 inches
6 0
3 years ago
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