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zzz [600]
2 years ago
13

HELP LOTS OF POINTS! I WILL GIVE YOU 100+ POINTS IF ANSWERED CORRECTLY!!!

Computers and Technology
1 answer:
Delicious77 [7]2 years ago
4 0

Answer:

E) all of the above

Explanation:

Your device can track your location, which means that it will tell where you've been. When you post on social media or just online, you are sharing what you're thinking. Your friends and family can easily be traced back to you, so they know who your friends and family are, and we leave evidence of what we've done because whatever you click gets tracked. hope this helps :)

You might be interested in
In Python, the data structure that stores elements of the same data type is called an array.
Serhud [2]

Answer:

Yes

Explanation:

An array is a homogeneous data structure (elements have same data type) that stores a sequence of consecutively numbered objects--allocated in contiguous memory. Each object of the array can be accessed by using its number (i.e., index). When you declare an array, you set its size.

3 0
3 years ago
Tim is in charge of the upcoming interschool baketball tournamnent. He wants to arrange all of the teams and their members in al
zalisa [80]
I think the answer is C.
7 0
3 years ago
Translate the following MIPS code to C. Assume that the variables f, g, h, i, and j are assigned to registers $s0, $s1, $s2, $s3
Romashka [77]

Answer:

f = 2 * (&A[0])

See explaination for the details.

Explanation:

The registers $s0, $s1, $s2, $s3, and $s4 have values of the variables f, g, h, i, and j respectively. The register $s6 stores the base address of the array A and the register $s7 stores the base address of the array B. The given MIPS code can be converted into the C code as follows:

The first instruction addi $t0, $s6, 4 adding 4 to the base address of the array A and stores it into the register $t0.

Explanation:

If 4 is added to the base address of the array A, then it becomes the address of the second element of the array A i.e., &A[1] and address of A[1] is stored into the register $t0.

C statement:

$t0 = $s6 + 4

$t0 = &A[1]

The second instruction add $t1, $s6, $0 adding the value of the register $0 i.e., 32 0’s to the base address of the array A and stores the result into the register $t1.

Explanation:

Adding 32 0’s into the base address of the array A does not change the base address. The base address of the array i.e., &A[0] is stored into the register $t1.

C statement:

$t1 = $s6 + $0

$t1 = $s6

$t1 = &A[0]

The third instruction sw $t1, 0($t0) stores the value of the register $t1 into the memory address (0 + $t0).

Explanation:

The register $t0 has the address of the second element of the array A (A[1]) and adding 0 to this address will make it to point to the second element of the array i.e., A[1].

C statement:

($t0 + 0) = A[1]

A[1] = $t1

A[1] = &A[0]

The fourth instruction lw $t0, 0($t0) load the value at the address ($t0 + 0) into the register $t0.

Explanation:

The memory address ($t0 + 0) has the value stored at the address of the second element of the array i.e., A[1] and it is loaded into the register $t0.

C statement:

$t0 = ($t0 + 0)

$t0 = A[1]

$t0 = &A[0]

The fifth instruction add $s0, $t1, $t0 adds the value of the registers $t1 and $t0 and stores the result into the register $s0.

Explanation:

The register $s0 has the value of the variable f. The addition of the values stored in the regsters $t0 and $t1 will be assigned to the variable f.

C statement:

$s0 = $t1 + $t0

$s0 = &A[0] + &A[0]

f = 2 * (&A[0])

The final C code corresponding to the MIPS code will be f = 2 * (&A[0]) or f = 2 * A where A is the base address of the array.

3 0
2 years ago
rapid prototyping could be an advantageous methodology for developing innovative computer-based instruction. Software engineers
frosja888 [35]

The option that is true for the Student Version above is option d:  This is not plagiarism.

<h3>What is plagiarism?</h3>

This is known to be the act of copying other people's work and then taking it as your own.

When you look at the student work, you will see some measures od differences. Hence, The option that is true for the Student Version above is option d:  This is not plagiarism.

Learn more about prototyping  from

brainly.com/question/14743515
#SPJ1

See  full question below

Original Source Material

There is a design methodology called rapid prototyping, which has been used successfully in software engineering. Given similarities between software design and instructional design, we argue that rapid prototyping is a viable method for instructional design, especially for computer-based instruction.

Student Version

Rapid prototyping could be an advantageous methodology for developing innovative computer-based instruction. Software engineers have been successful in designing applications by using rapid prototyping. So it also could be an efficient way to do instructional design.

Which of the following is true for the Student Version above?

a. Word-for-Word plagiarism

b. Paraphrasing plagiarism

c. This is not plagiarism

8 0
2 years ago
A company operates on two types of servers: 2 large servers (L) and 4 smaller servers (S), with a combined total of 64GB RAM. Th
kati45 [8]

Explanation:

Let the size of a large server be L, and

the size of a small server be S.

We are given two scenarios,

2L+4S = 64.............(1)

and

L+3S = 40...............(2)

We solve the equations as follows

2(2)-(1)

2L-2L +6S-4S = 2*40-64

2S = 16

so S=8 ..................(3), size of small server

substitute (3) in (2)

L+3(8) =40

L = 40-24 = 16..............size of large server

8 0
3 years ago
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