Answer:
No
Explanation:
No matter where an object is, its mass will stay the same, but its weight might change depending on gravity.
If you want individual total momentum,
it depends
- on the masses of the marbles
- on the velocities before impact
- on the velocities after impact
- was it elastic pre/post impact (bounced off)?
- was it inelastic pre/post impact (stuck a)?
with the given info, we must assume masses and velocities of the two marbles are the same which means there are 4 possible answers. If the question is suggesting that their INDIVIDUAL momentums were 0.12 kg*m/s vs. their COMBINED momentum (0.06 kg*m/s) before impact.
1. combined momentum & inelastic
0.06 kg*m/s = (m+m)*v
0.03 kg*m/s = m×v
2. individual momentum & inelastic
0.12 kg*m/s = (m+m)*v
0.06 kg*m/s = m×v
3. combined momentum & elastic
0.06 kg*m/s = m×v1f + m×v2f (b/c vf is different)
0.06 kg*m/s = m×(v1f + v2f)
4. individual momentum & elastic
0.12 kg*m/s = m×v1f + m×v2f (b/c vf is same)
0.06 kg*m/s = m×v
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IF you want COMBINED total momentum, apply law of conservation of momentum which states that momentum is conserved without external forces... so it would be the same.
0.06 kg×m/s
Answer:
mass = 36.92 kg
Explanation:
We have given the torque
Radius of the disk r = 0.50 m
Angular acceleration
We know that torque is given by here I is moment of inertia and is angular acceleration
So
Moment of inertia is given by
m = 36.92 kg
The given answer is not matched with this answer but after calculation i got m =36.92 kg
Answer:
The potential energy of the hiker is .
Explanation:
Given that,
Mass of the hiker, m = 61 kg
Height above sea level, h = 1900 m
We need to find the potential energy associated with a 61-kg hiker atop New Hampshire's Mount Washington. The potential energy is given by :
g is the acceleration due to gravity
So, the potential energy of the hiker is . Hence, this is the required solution.
Answer:
Speed of the satellite V = 6.991 × 10³ m/s
Explanation:
Given:
Force F = 3,000N
Mass of satellite m = 500 kg
Mass of earth M = 5.97 × 10²⁴
Gravitational force G = 6.67 × 10⁻¹¹
Find:
Speed of the satellite.
Computation:
Radius r = √[GMm / F]
Radius r = √[(6.67 × 10⁻¹¹ )(5.97 × 10²⁴)(500) / (3,000)
Radius r = 8.146 × 10⁶ m
Speed of the satellite V = √rF / m
Speed of the satellite V = √(8.146 × 10⁶)(3,000) / 500
Speed of the satellite V = 6.991 × 10³ m/s