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Veronika [31]
4 years ago
7

A child in about those 85.15 kg package out horizontally with a speed of 10 m/s the mass of the child is 27.2 kg in the mass of

the ball is very 3.8 kg calculate the velocity of the ball immediately after assuming it was initially at rest
Physics
1 answer:
rosijanka [135]4 years ago
7 0

Nothing happened to make me change my opinion.  So, immediately after assuming it was at rest, I still believed the ball was at rest.  That is, its velocity was still zero in every direction.

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. If an 8 N force pulled a 3.0 kg object to the left and a 5 N force pushed it to the right,
maxonik [38]

Answer:

8-5=3

The bigger force is to the left

3N to the left

Explanation:

7 0
1 year ago
During normal beating, the heart creates a maximum 3.60 mV potential across 0.250 m of a person's chest, creating a 1.00 Hz elec
grandymaker [24]

Answer:

The maximum electric field strength is 0.0144 V/m.

Explanation:

Given that,

Electric potential created in the heart, V = 3.6 mV

Distance, d= 0.25 m

Frequency of the the electromagnetic wave, f = 1 Hz

We need to find the maximum electric field strength created. We know that the electric potential is given by :

V=Ed

E is the maximum electric field strength

E=\dfrac{V}{d}\\\\E=\dfrac{3.6\times 10^{-3}\ V}{0.25\ m}\\\\E=0.0144\ V/m

So, the maximum electric field strength is 0.0144 V/m. Hence, this is the required solution.

5 0
3 years ago
The pictures represent three different states of matter.
Veronika [31]

ONLY if ur asking for the 3 states of matter it is solid liquid and gas

4 0
4 years ago
Be sure to answer all parts. Without stratospheric ozone (O3), harmful solar radiation would cause gene alterations. Ozone forms
Ratling [72]

Answer:

for C-Cl  bond \lambda_1=3.66\times 10^{-9}\ m

for O-O bond \lambda_2=2.43\times 10^{-9}\ m

Explanation:

  • We have the bond enegy for C-Cl, BE_1=327\ kJ.mol^{-1}= 327000\times 1.66\times 10^{-22}\ J\ per\ molecule
  • bond enegy for C-Cl, BE_2=494\ kJ.mol^{-1}= 494000\times 1.66\times 10^{-22}\ J\ per\ molecule

<u>Now as we know the energy of electromagnetic waves is given by:</u>

E=h.\nu

here E = BE

<u>Then for C-Cl:</u>

327000\times 1.66\times 10^{-22}=6.63\times 10^{-34}\times \nu_1

\nu_1=8.18733\times 10^{16}\ Hz

Now wavelength:

\lambda_1=\frac{c}{\nu_1}

\lambda_1=\frac{3\times 10^8}{8.18733\times 10^{16}}

\lambda_1=3.66\times 10^{-9}\ m

<u>For O2:</u>

494000\times 1.66\times 10^{-22}=6.63\times 10^{-34}\times \nu_2

\nu_2=1.236863\times 10^{17}\ Hz

Now wavelength:

\lambda_2=\frac{c}{\nu_2}

\lambda_2=\frac{3\times 10^8}{1.236863\times 10^{17}}

\lambda_2=2.43\times 10^{-9}\ m

8 0
3 years ago
La taille d'un molécule d'eau est 0,4nm
pogonyaev
2mm.
0,4x 5x10^6 = 2x10^6
1nm = 1x10^-6mm
2x10^6nm = 2mm.
8 0
3 years ago
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