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charle [14.2K]
3 years ago
13

You are designing a new home for a cold climate. You want one room in the house to be warmed by the Sun's energy. Which material

would be best to use for transmitting visible light into the room? A. Concrete B. Wood O C. Glass D. Brick​
Physics
2 answers:
solniwko [45]3 years ago
8 0

Answer:

glass if for a good view, but for absorbing heat concrete and brick is the best

Explanation:

wood is not a good idea bc it can cause fires from too much heat and it absorbs less heat but all of that depends on how good the material your using

Pachacha [2.7K]3 years ago
4 0

Answer:

it would be glass

Explanation:

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A woman drives 6 miles, accelerating uniformly from rest to 70 mph. How long does it take for her to reach 70 mph?
Morgarella [4.7K]
Using the two kinematic equations that can be used for this problem are:
Vf = Vi + at and d=Vit +(1/2)*at^2
Since Vi (initial velocity) = 0 

The equations can further be simplified where a is the acceleration, t is the time, Vf is the final velocity which is 70 miles per hour and d is 6 miles

Vf = at
70 = at
a = 70/t---equation 1

d=(1/2)*a*(t^2)
6 = (1/2)*a*(t^2) ---equation 2

Substituting equation 1 to equation 2.
6= (1/2)*(70/t)*(t^2)
6= 35t
t= 0.17142 hours or 10.28571 mins or 617.14 sec



6 0
3 years ago
) Calculate current passing in an electrical circuit if you know that the voltage is 8 volts and the resistance is 10 ohms
Svetach [21]

Explanation:

<em>Hey</em><em>,</em><em> </em><em>there</em><em>!</em>

<em>Here</em><em>,</em><em> </em><em>In</em><em> </em><em>question</em><em> </em><em>given</em><em> </em><em>that</em><em>, </em>

<em>potential</em><em> </em><em>difference</em><em> </em><em>(</em><em>V</em><em>)</em><em>=</em><em> </em><em>8</em><em>V</em>

<em>resistance</em><em> </em><em>(</em><em>R</em><em>)</em><em>=</em><em> </em><em>1</em><em>0</em><em> </em><em>ohm</em>

<em>Now</em><em>,</em>

<em>According</em><em> </em><em>to</em><em> </em><em>the</em><em> </em><em>Ohm's</em><em> </em><em>law</em><em>,</em>

<em>V</em><em>=</em><em> </em><em>R</em><em>×</em><em>I</em><em> </em><em> </em><em> </em><em> </em><em>{</em><em> </em><em>where</em><em> </em><em>I</em><em> </em><em>=</em><em> </em><em>current</em><em>}</em>

<em>or</em><em>,</em><em> </em><em>I</em><em> </em><em>=</em><em> </em><em>V</em><em>/</em><em>R</em>

<em>or</em><em>,</em><em> </em><em>I</em><em> </em><em>=</em><em> </em><em>8</em><em>/</em><em>1</em><em>0</em>

<em>Therefore</em><em>, </em><em> </em><em>current</em><em> </em><em>is</em><em> </em><em>4</em><em>/</em><em>5</em><em> </em><em>A</em><em> </em><em>or</em><em> </em><em>0</em><em>.</em><em>8</em><em> </em><em>A</em><em>.</em>

<em>(</em><em>A</em><em>=</em><em> </em><em>ampere</em><em> </em><em>=</em><em> </em><em>unit</em><em> </em><em>of</em><em> </em><em>current</em><em>)</em><em>.</em>

<em><u>Hope it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em><em> </em>

6 0
4 years ago
You toss a tennis ball straight upward. At the moment it leaves your hand it is at a height of 1.5 m above the ground, and it is
ollegr [7]

My answer was incorrect, please disregard.

4 0
3 years ago
When he reaches the bottom, 4.2 m below his starting point, his speed is 2.2 m/s . By how much has thermal energy increased duri
Advocard [28]

Complete question:

A fireman of mass 80 kg slides down a pole. When he reaches the bottom, 4.2 m below his starting point, his speed is 2.2 m/s. By how much has thermal energy increased during his slide?

Answer:

The thermal energy increased by 3,099.2 J

Explanation:

Given;

mass of the fireman, m = 80 kg

initial position of the fireman, hi = 4.2 m

final speed, v = 2.2 m/s

The change in the thermal energy is calculated as;

ΔE +  (K.Ef - K.Ei) + (Uf - Ui) = 0

where;

ΔE is the change in the thermal energy

K.Ef is the final kinetic energy

K.Ei is the initial kinetic energy

Uf is the final potential energy

Ui is the initial potential energy

\Delta  E_{th} +  (\frac{1}{2} mv_f^2 - \frac{1}{2} mv_i^2) + (mgh_f - mgh_i)=0\\\\initial \ velocity, \ v_i = 0\\final \ height , \ h_f = o\\\\\Delta  E_{th} + (\frac{1}{2} mv_f^2) + ( - mgh_i)=0\\\\\Delta  E_{th} +  \frac{1}{2} mv_f^2 - mgh_i = 0\\\\\Delta  E_{th} =mgh_i  - \frac{1}{2} mv_f^2\\\\\Delta  E_{th} =  80 \times 9.8 \times 4.2  \ \ - \ \ \frac{1}{2} \times 80 \times (2.2)^2  \\\\\Delta  E_{th} = 3292.8 \ J \ - \ 193.6 \ J\\\\\Delta  E_{th} = 3,099.2 \ J

3 0
3 years ago
A radioactive sample has a count rate of 10,000 Bq. 24 days later the activity has fallen to 625 Bq. What is the half-life of th
joja [24]

Answer:

10000 Bq / 625 Pq = 16

Radioactivity has decreased by a factor of 16

2^4 = 16

So the sample has gone thru 4 half-lives

24 da / 4 = 6 da

6 da is the half-life

6 0
2 years ago
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