Answer:
D.
Explanation:
To solve the problem it is necessary to apply the concepts of Destructive and constructive interference. The constructive interference in tin film is given by
Where,
t = thickness
Wavelenght
m= is an integer
n= film/refractive index
We use this equaton because phase change is only present for gasoline air interface, but not at the gasoline-water interface. <em>The minimum t only would be when the value of m=0 then</em>
Therefore the correct answer is D. The minimum thickness of the film to see ab right reflection is 100nm
When a motorboat passes by, a disturbance or vibration in the lake water is created which travels in all the directions. A water wave is a combination of longitudinal wave as well as transverse wave. If you are a particle of water in the lake, then you would be hit by nearby water particle which would set you in motion. you would travel up and down forming crest and trough and sideways. The energy would be transported forward, as you would collide with other particle and the wave moves forward. your position would not change. only the energy would be transported.
Explanation:
It is given that,
Length of the poster, l = 0.95 m
Breadth of the poster, b = 1 m
The poster is in the shape of rectangle. For a rectangular shape, perimeter is equal to :
P = 2(l+b)
P=2(0.95+1)
P=3.9 m
(b) One digits, P = 4 m
(c) Two digits, P = 3.9 m
(d) Three digits, P = 3.90 m
Answer:
28.5 m/s
Explanation:
The speed has two orthogonal components, horizontal and vertical. To decompose the speed into these components we can use these trigonometric equations:
Vh = V * cos(a)
Vv = V * sin(a)
The forwards velocity is the horizontal component, so we use
Vh = V * cos(a)
Vh = 50 * cos(55)
Vh = 50 * 0.57
Vh = 28.5 m/s
Answer:
a) 4.8×10^-5T
b) 7.38×10^-7seconds
Explanation:
The centripetal force in a magnetic field is given by:
qvB= mv2/r
Where q= charge of the ion
m= mass of the ion
r= radius of the circular path
B= magnetic field
V= velocity
Rearranging to make B subject of formular gives:
B=mv/r
B= [(9.11×10^-31)×(5.87×10^5)]/ [(1.6×10^-19)×(6.81×10^-2)]
B = (5 34×10^-25)/(1.099×10^-20)
B= 4.86×10^-5T
b) T =( 2 pi × r)/v
T = 2 × 3.142 x (6.81×10^-2) / (5.87×10^5
T = 0.428/ (5.87×10^5)
T = 7.38 × 10^-7seconds