If the probes are identical, then the one that feels a larger gravitational
force is orbiting closer to Jupiter than the other one is.
If they're not identical, then the one with greater mass will feel more
gravitational force than the one with less mass, even if they're both
the same distance from Jupiter. (We know this from the experimental
observation that fatter people weigh more, even on Earth.)
Answer:
AB = DE <CD <BC
Explanation:
This is an exercise in kinetics, the accelerations defined as the change in velocity over the time interval, therefore the accelerations of a vector.
Because the acceleration is a vector, it has two parts, the modulus that the numerical value of the magnitude and the direction, a change in any of them implies the existence of a relationship.
Let's apply these reasoning to our problem.
AB Path
this path is straight and as they indicate that the constant speed the acceleration is zero
DE path
This path is straight and since the velocity is constant the zero steps
BC path
This path is a curve and the velocity modulus is constant, but its directional changes therefore there is an acceleration called centripetal, given by the expression
= v² / r
where r is the radius of the curve and the direction of acceleration is towards the center of the curve
CD path
This path is a curve and it also has centripetal acceleration, as can be seen in the drawing, the radius of the curve is greater than in section BC, therefore the acceleration is less
>
In summary lower accelerations are
AB = DE <CD <BC
The man because the train is moving 72 mph not the man
The average force on the shell while it is in the gun barrel is 10,869,833.33N.
<h3>HOW TO CALCULATE FORCE?</h3>
Force applied on an object can be calculated by multiplying the mass of the object by its acceleration.
However, the acceleration needs to be calculated by using the following equation:
v² - u² = 2as
Where;
- v = final velocity
- u = initial velocity
- a = acceleration
- s = distance
770² - 0² = 2 (a)(1.5)
592900 = 3a
a = 197633.3m/s²
Force = 55kg × 197633.3m/s²
Force = 10,869,833.33N
Therefore, the average force on the shell while it is in the gun barrel is 10,869,833.33N.
Learn more about force at: brainly.com/question/26115859
Answer:
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Explanation:
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