Question

Assign numMatches with the number of elements in userValues that equal matchValue. userValues has NUM_VALS elements. Ex: If userValues is {2, 1, 2, 2} and matchValue is 2 , then numMatches should be 3. Your code will be tested with the following values:
matchValue: 2, userValues: {2, 1, 2, 2} (as in the example program above)
matchValue: 0, userValues: {0, 0, 0, 0}
matchValue: 10, userValues: {20, 50, 70, 100}
#include
#include
using namespace std;
int main() {
const int NUM_VALS = 4;
int matchValue;
unsigned int i;
int numMatches = -99; // Assign numMatches with 0 before your for loop
vector userValues(NUM_VALS);
cin >> matchValue;
for (i = 0; i < userValues.size(); ++i) {
cin >> userValues.at(i);
}
/* Your solution goes here */
cout << "matchValue: " << matchValue << ", numMatches: " << numMatches << endl;
return 0;
}

Answer 1

Answer:

Replace /* Your solution goes here */ with:

cin>>matchValue;

numMatches = 0;

for (i = 0; i < userValues.size(); ++i) {

if(matchValue == userValues.at(i))

{

numMatches++;

}

}

Explanation:

This line gets input for matchValue

cin>>matchValue;

This line initializes numMatches to 0

numMatches = 0;

The following iteration checks for the number of matches (numMatches) of the matchValue

for (i = 0; i < userValues.size(); ++i) {

if(matchValue == userValues.at(i))

{

numMatches++;

}

}

See Attachment for full source code

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