Answer: Multi-user issue
Explanation: A database management system scheme can have multi-user issue when the designing of the system is not made properly. The multi user issue rises when the users concurrently access the data from the database and related error get invoked due to some reason like repeatable reading issue, serialization, etc.
The reading problem is usually can be related to reading of the database in uncommitted manner, uncommitted reading, repeatedly reading etc.Thus, Cora and Owen are accessing the database concurrently which can create multi-user issue.
L is a decidable language because the Turing machine accepts it.
L is a recognizable language if TM M recognizes it.
<h3>How do you know if a language is decidable?</h3>
A language is said to be decidable only when there seems to exists a Turing machine that is said to accepts it,
Here, it tends to halts on all inputs, and then it answers "Yes" on words that is seen in the language and says "No" on words that are not found in the language. The same scenario applies to recognizable language.
So, L is a decidable language because the Turing machine accepts it.
L is a recognizable language if TM M recognizes it.
Learn more about programming language from
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Answer:
People in households buy goods and services from businesses in an attempt to satisfy their unlimited needs and wants.
Explanation:
Households also sell their labor, land, and capital in exchange for income that they use to buy goods and services that firms produce.
Answer:
(config)# enable password secret
(config)# enable secret Encrypted_Password
(config-line)# password secret
(config)# enable secret Secret_Password
(config)# service password-encryption
Explanation:
To prevent all configured passwords from appearing in plain text in configuration files, an administrator can execute the service password-encryption command. This command encrypts all configured passwords in the configuration file. For more: https://ccnav7.net/what-command-will-prevent-all-unencrypted-passwords-from-displaying-in-plain-text-in-a-configuration-file-2/
Answer:
Written in C++
void number(int n){
if(n%2 == 0)
cout<<2 * n;
else
cout<<5 * n;
}
Explanation:
The programming language is not stated.
However, I answered using C++
This line defines the function as void
void number(int n){
This line checks if the number is even
if(n%2 == 0)
If yes, it doubles the number and prints the output
cout<<2 * n;
If otherwise,
else
It multiplies the number by 5 and prints the output
cout<<5 * n;
}
To call the function from main, use:
number(n);
Note than n must be declared as integer
See attachment
