1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Mashutka [201]
4 years ago
7

Someone help me with this

Mathematics
2 answers:
muminat4 years ago
4 0
Shaded as a fraction:40/100

Decimal form:0.4

Percentage:40%
I hope this was correct and hope it helps:)
krok68 [10]4 years ago
3 0

Answer:

40/60

Step-by-step explanation:

You might be interested in
You have no more than $65 to spend after paying your bills. You want a drink that costs
-BARSIC- [3]

Answer: B

Step-by-step explanation: You have no more than $65 which means you will want to spend equal to or less. Since you have $65, you will be able to spend up to that amount but you will not be able to spend any more than that. So, you will need to make sure the final price remains under or equal to your amount.

8 0
3 years ago
Using exponents don't understand what's 9 cubed and 20 squared how do I do it in expanded form whett
Naily [24]
Expanded form is when you just write it out.

so 9 cubed becomes:

9×9×9

and 20 squared becomes:

20×20

the exponent tells you how many times to multiply that number by itself. so, whenever it asks for expanded form, you just write the number how ever many times the exponent tells you to and multiply them all.
4 0
3 years ago
Pls help fast i will mark brainlyiest
Leona [35]

The mean temperature of the orange juice is 5 °F <u>greater than</u> the mean temperature of the water

<h3>Calculating Average</h3>

From the question, we are to calculate how much greater the mean temperature of the orange juice is than the mean temperature of the water

From the given chart,

Mean temperature of orange juice = \frac{59+65+72+78+85+81}{6}

Mean temperature of orange juice = \frac{440}{6}

Mean temperature of orange juice = 73.33 °F

Mean temperature of water = \frac{55+62+68+71+79+75}{6}

Mean temperature of water = \frac{410}{6}

Mean temperature of water = 68.33 °F

Difference in temperature = 73.33 °F - 68.33 °F

Difference in temperature = 5 °F

Hence, the mean temperature of the orange juice is 5 °F <u>greater than</u> the mean temperature of the water

Learn more on Calculating average here: brainly.com/question/17102414

#SPJ1

5 0
2 years ago
Micheal is three time as old as Jean in seven year he will be twice old as she will be then how old are they both
PtichkaEL [24]

Answer:

Michael is 21 years old while Jean is 7 years old.

Step-by-step explanation:

Given that Micheal is three times as old as Jean, but in seven years he will be twice old as she will be, to determine how old are they both at this time, the following calculation must be performed:

M = 3J

M + 7 = 2J + 7

7 = 1/3

7 x 3 = 21

21 + 7 = 28

7 + 7 = 14

21 / 7 = 3

28 / 14 = 2

 

Therefore, Michael is 21 years old while Jean is 7 years old.

5 0
3 years ago
Which is the graph of f(x) =3 sqrtx/4?
Ket [755]

Step-by-step explanation:

f(x) = 3√x /4

x=0 => y = 0

x=1 => y = 0.75

x=4 => y = 1.5 ==> (4, 1.5)

x=16=>y= 3

the right answer is the second graph

3 0
3 years ago
Other questions:
  • Which statement is true about the value of |-5|
    10·1 answer
  • What is the geometric mean of 7 and 9?
    6·2 answers
  • A rectangle has an area of 21x+81. If the width is 3 units, what is the length of the rectangle
    8·1 answer
  • Somebody please help
    15·1 answer
  • Factoring trinomials<br> Select two for each
    5·2 answers
  • What is 123% of $938.55?<br><br> Round your answer to the nearest cent
    12·1 answer
  • Can someone help me on this? Quite lost
    11·1 answer
  • 1+1=?<br> im bored <br> :P<br><br> heheheheheheheheheheheheheh
    9·2 answers
  • 9. There are 56 children who need to be divided into teams of 8. How many children will
    15·1 answer
  • Solve the following.
    9·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!