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Marat540 [252]
3 years ago
14

Is thus correct domain and range using interval notation?

Mathematics
1 answer:
natita [175]3 years ago
6 0
Yes the domain represents the X vales and range represents the Y values
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How are rigid transformations used to justify the sas congruence theorem?
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Answer:Rigid transformations preserve segment lengths and angle measures.

A rigid transformation, or a combination of rigid transformations, will produce congruent figures.

In proving SAS, we started with two triangles that had a pair of congruent corresponding sides and congruent corresponding included angles.

We mapped one triangle onto the other by a translation, followed by a rotation, followed by a reflection, to show that the triangles are congruent.


Step-by-step explanation:

Sample Response: Rigid transformations preserve segment lengths and angle measures. If you can find a rigid transformation, or a combination of rigid transformations, to map one triangle onto the other, then the triangles are congruent. To prove SAS, we started with two distinct triangles that had a pair of congruent corresponding sides and a congruent corresponding included angle. Then we performed a translation, followed by a rotation, followed by a reflection, to map one triangle onto the other, proving the SAS congruence theorem.

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D is the correct answer
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The growth of a population of mountain lions can be described by the function f(x) = 500(1.015)^x, where x is the number of year
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6 0
3 years ago
PLEASE HELP I NEED THIS NOW SO BADLY :(( Simplify: 2 1/4 x+(4 1/3 x−7 4/5 )÷2 3/5
prohojiy [21]

Answer:

2\frac{1}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \:2\frac{3}{5} = \frac{47x-36}{12}

Step-by-step explanation:

Considering the expression

2\frac{1}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \:2\frac{3}{5}

Simplifying the expression

\frac{1}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \:2\frac{3}{5}

\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 2\frac{1}{4}=\frac{9}{4}

\frac{9}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \frac{13}{5}

\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 2\frac{3}{5}=\frac{13}{5}

\frac{9}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \frac{13}{5}

\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 4\frac{1}{3}=\frac{13}{3}

\frac{9}{4}x+\left(\frac{13}{3}x-7\frac{4}{5}\right)\div \frac{13}{5}

\mathrm{Convert\:mixed\:numbers\:to\:improper\:fractions}:\quad 7\frac{4}{5}=\frac{39}{5}

\frac{9}{4}x+\left(\frac{13}{3}x-\frac{39}{5}\right)\div \frac{13}{5}

As

\frac{9}{4}x=\frac{9x}{4}

and

\frac{\frac{13}{3}x-\frac{39}{5}}{\frac{13}{5}}=\frac{5\cdot \frac{65x-117}{15}}{13}

So,

\frac{9x}{4}+\frac{5\cdot \frac{65x-117}{15}}{13}

\mathrm{Least\:Common\:Multiplier\:of\:}4,\:13:\quad 52

\mathrm{Adjust\:Fractions\:based\:on\:the\:LCM}

\frac{117x}{52}+\frac{\frac{4\left(65x-117\right)}{3}}{52}

\mathrm{Since\:the\:denominators\:are\:equal,\:combine\:the\:fractions}:\quad \frac{a}{c}\pm \frac{b}{c}=\frac{a\pm \:b}{c}

\mathrm{Join}\:117x+\frac{4\left(65x-117\right)}{3}:\quad \frac{611x-468}{3}

\frac{\frac{611x-468}{3}}{52}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}

\frac{611x-468}{3\cdot \:52}

\mathrm{Multiply\:the\:numbers:}\:3\cdot \:52=156

\frac{611x-468}{156}

\mathrm{Factor}\:611x-468:\quad 13\left(47x-36\right)

\frac{13\left(47x-36\right)}{156}

\mathrm{Cancel\:the\:common\:factor:}\:13

\frac{47x-36}{12}

Therefore, 2\frac{1}{4}x+\left(4\frac{1}{3}x-7\frac{4}{5}\right)\div \:2\frac{3}{5} = \frac{47x-36}{12}

Keywords: algebraic expression , simplification

Learn more about algebraic expression from brainly.com/question/11336599

#learnwithBrainly

7 0
4 years ago
Someone please help me with these. I forgot how to do these. Need within a hour
Soloha48 [4]
I also forgot man‍ but if you wanna be nice and give me brainliest that would be appreciated
5 0
3 years ago
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