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qwelly [4]
3 years ago
8

22. Geography The average elevation of the city of New Orleans, Louisiana, is 0.5 m below sea level. The highest point in Louisi

ana is Driskill Mountair at about 163.5 m higher than New Orleans. How high is Driskill Mountain

Mathematics
1 answer:
Vikki [24]3 years ago
8 0
Driskill Mountain is 163.5m-.5m = 163m above sea level. 
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What is the approximate distance around the half circle with radius 12 centimeters?
Katarina [22]
You can find the perimeter of a circle by using the radius.
circumference = 2 \pi r
Circumference = 2 \pi x 12
circumference = 24 pi
Since you are only trying to find half of the circle you would divide your answer by 2 

24pi / 2 = 12 pi

12 pi = 37.68

The answer is B. 37.7
4 0
3 years ago
A gardener has a cylindrical planter that has a radius of 12 inches and is 2 feet deep what is the approximate number of cubic f
kobusy [5.1K]

Answer:

2 feet of soil

Step-by-step explanation:

8 0
3 years ago
A swimming pool with a volume of 30,000 liters originally contains water that is 0.01% chlorine (i.e. it contains 0.1 mL of chlo
SpyIntel [72]

Answer:

R_{in}=0.2\dfrac{mL}{min}

C(t)=\dfrac{A(t)}{30000}

R_{out}= \dfrac{A(t)}{1500} \dfrac{mL}{min}

A(t)=300+2700e^{-\dfrac{t}{1500}},$  A(0)=3000

Step-by-step explanation:

The volume of the swimming pool = 30,000 liters

(a) Amount of chlorine initially in the tank.

It originally contains water that is 0.01% chlorine.

0.01% of 30000=3000 mL of chlorine per liter

A(0)= 3000 mL of chlorine per liter

(b) Rate at which the chlorine is entering the pool.

City water containing 0.001%(0.01 mL of chlorine per liter) chlorine is pumped into the pool at a rate of 20 liters/min.

R_{in}=(concentration of chlorine in inflow)(input rate of the water)

=(0.01\dfrac{mL}{liter}) (20\dfrac{liter}{min})\\R_{in}=0.2\dfrac{mL}{min}

(c) Concentration of chlorine in the pool at time t

Volume of the pool =30,000 Liter

Concentration, C(t)= \dfrac{Amount}{Volume}\\C(t)=\dfrac{A(t)}{30000}

(d) Rate at which the chlorine is leaving the pool

R_{out}=(concentration of chlorine in outflow)(output rate of the water)

= (\dfrac{A(t)}{30000})(20\dfrac{liter}{min})\\R_{out}= \dfrac{A(t)}{1500} \dfrac{mL}{min}

(e) Differential equation representing the rate at which the amount of sugar in the tank is changing at time t.

\dfrac{dA}{dt}=R_{in}-R_{out}\\\dfrac{dA}{dt}=0.2- \dfrac{A(t)}{1500}

We then solve the resulting differential equation by separation of variables.

\dfrac{dA}{dt}+\dfrac{A}{1500}=0.2\\$The integrating factor: e^{\int \frac{1}{1500}dt} =e^{\frac{t}{1500}}\\$Multiplying by the integrating factor all through\\\dfrac{dA}{dt}e^{\frac{t}{1500}}+\dfrac{A}{1500}e^{\frac{t}{1500}}=0.2e^{\frac{t}{1500}}\\(Ae^{\frac{t}{1500}})'=0.2e^{\frac{t}{1500}}

Taking the integral of both sides

\int(Ae^{\frac{t}{1500}})'=\int 0.2e^{\frac{t}{1500}} dt\\Ae^{\frac{t}{1500}}=0.2*1500e^{\frac{t}{1500}}+C, $(C a constant of integration)\\Ae^{\frac{t}{1500}}=300e^{\frac{t}{1500}}+C\\$Divide all through by e^{\frac{t}{1500}}\\A(t)=300+Ce^{-\frac{t}{1500}}

Recall that when t=0, A(t)=3000 (our initial condition)

3000=300+Ce^{0}\\C=2700\\$Therefore:\\A(t)=300+2700e^{-\dfrac{t}{1500}}

3 0
3 years ago
HELPPPPPPPPPPPPPPPPPPP
Anna11 [10]

Answer:

<em>5 ; 27 points</em>

Step-by-step explanation:

6x - 3 = x + 12

5x = 15

<em>x = 5</em>

GF = 6(5) - 3 = <em>27 units </em>

3 0
3 years ago
2x+10=5y-4 solve for x
scoundrel [369]

Answer: x=2.5y-7

Step-by-step explanation:

Subtract 10 from both sides, resulting in 2x=5y-14

Divide both sides by 2 to isolate the x, resulting in x=(5/2)y-7

5 0
3 years ago
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