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Bezzdna [24]
3 years ago
7

Is (4, -2) the solution of the system of equations shown

Mathematics
1 answer:
Advocard [28]3 years ago
8 0

No, because if you substitute (4, -2) into x and y in each equation, they are not the same as the value on the right side of the equation.

2(4) + 4(-2) = - 2

8 + -8 = -2

0 = -2 <---- this is not correct.

-4(4) + -2 = -14

-16 + -2 = -14

-18 = -14 <----- this is not correct.

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a rectangular garden has dimensions of 100 feet by 10, next season, the garden decreased to 2/5 of its size. what is the scale o
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Answer: 40 ft by 4 ft

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3 years ago
URGENT AND SIMPLE question pls:))) You dont have to do all of it, if you could just give me the equation for this problem, that
Mashcka [7]

If Ann can build the model in 3 hours, then in 1 hour she gets 1/3 of it done. Likewise, if Sam can build the model in 6 hours, then in 1 hour he gets 1/6 of it done. We are looking to find how long it takes when they combine their efforts, so we will add the two together and set it equal to 1/x, x being the number of hours it takes for both of them to get the whole job done. The equation then looks like this: \frac{1}{3}+\frac{1}{6}=\frac{1}{x}. You will have to find the common denominator to add those fractions, and once you do, cross multiply to solve for x.

5 0
3 years ago
Simplify the linear expression
vekshin1

Answer:

\huge\boxed{-\frac{7}{8}a - \frac{1}{6}}

Step-by-step explanation:

This question utilizes combining like terms and common denominators. First you have to convert both terms including "a" to have a denominator of 8. You would do this by multiplying both the numerator, and the denominator by the same value. This value in the case of -\frac{1}{4} a would be 2, and in the case of \frac{2}{3} the value would be 2. This would result in the equation: -\frac{5}{8}a+\frac{4}{6}-\frac{2}{8}a-\frac{5}{6}. Then simply combine like terms to get your final answer.

5 0
2 years ago
The line tangent to the graph of g(x) = x^{3}-4x+1 at the point (2, 1) is given by the formula
Usimov [2.4K]

well, about A and D, I just plugged the values on the slope formula of

\bf \begin{array}{llll} g(x)=x^3-4x+1\\ L(x) = 8(x-2)+1 \end{array} \qquad \begin{cases} x_1=1.9\\ x_2=2.1 \end{cases}\implies \cfrac{f(b)-f(a)}{b-a}

for A the values are 8.01 and 8.0, so indeed those "slopes" are close. \textit{\huge \checkmark}

for D the values are -2.25 and 8.0, so no dice on that one.

for B, let's check the y-intercept for g(x), by setting x = 0, we end up g(0) = 0³-4(0)+1, which gives us g(0) = 1.

checking L(x) y-intercept, well, L(x) is in slope-intercept form, thus the +1 sticking out on the far right is the y-intercept, so, dice. \textit{\huge \checkmark}

for C, well, the slope if L(x) is 8, since it's in slope-intercept form, the derivative of g(x) is g'(x) = 3x² - 4, and thus g'(0) = -4, so no dice.

for E, do they intercept at (2,1)?  well, come on now, L(x) is a tangent line to g(x), so that's a must for a tangent. \textit{\huge \checkmark}

for F, we know the slope of the line L(x) is 8, is g'(2) = 8?  let's check

recall that g'(x) = 3x² - 4, so g'(2) = 3(2)² - 4, meaning g'(2) = 8, so, dice. \textit{\huge \checkmark}

6 0
3 years ago
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