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Vanyuwa [196]
3 years ago
13

Jane marko buys a car for 43,900.00.

Mathematics
1 answer:
ikadub [295]3 years ago
4 0
22828.l of a period of 3 years.
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This question is really hard for me.Please answer.
GarryVolchara [31]
The correct answer is 13
4 0
2 years ago
The yearbook club is handing out T-shirts to its members. There are 5 blue, 7 green, 9 red, and 4 yellow T-shirts in all. If Jac
damaskus [11]

Answer:

n(R)=9

n(Y)=4

n(B)=5

n(G)=7

n(s)25

probability of getting red =n(R)/n(S)=9/25

6 0
3 years ago
How many zeros are in the product of any nonzero whole number and 1000?Explain your answer
kotegsom [21]

Answer:

At least 3.

Step-by-step explanation:

It depends on the  whole number.

For example 53 * 1000 = 53,000 (3 zeros).

101 * 1000 = 101,000  (4 zeros).

8 0
3 years ago
Prove that in each triangle the total angles are 180 degrees
dmitriy555 [2]

This is a proof that the angles in a triangle equal 180°:

The top line (that touches the top of the triangle) is
running parallel to the base of the triangle.

So:

<span> <span>angles A are the same </span> <span>angles B are the same </span> </span>

And you can easily see that A + C + B does a complete rotation from one side of the straight line to the other, or <span>180°</span>

8 0
3 years ago
Read 2 more answers
An optical inspection system is used to distinguish among different part types. The probability of a correct classification of a
MAVERICK [17]

Answer:

Probability Mass Function:

   x:          0                         1                            2                          3

P(x):          0.000064          0.004608             0.115902             0.884736

Step-by-step explanation:

We are given the following information:

We treat correct classification  as a success.

P(correct classification) = 0.96

Then the number of classification follows a binomial distribution, where

P(X=x) = \binom{n}{x}.p^x.(1-p)^{n-x}

where n is the total number of observations, x is the number of success, p is the probability of success.

Now, we are given n = 3 and x = 0, 1, 2, 3

We have to evaluate:

P(x = 0)\\= \binom{3}{0}(0.96)^0(1-0.96)^3\\=0.000064

P(x = 1)\\= \binom{3}{1}(0.96)^1(1-0.96)^2\\=0.004608

P(x = 2)\\= \binom{3}{2}(0.96)^2(1-0.96)^1\\=0.115902

P(x = 3)\\= \binom{3}{3}(0.96)^3(1-0.96)^0\\=0.884736

PMF:

   x:          0                         1                            2                          3

P(x):          0.000064          0.004608             0.115902             0.884736

8 0
2 years ago
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