The better deal is 1 gallon of milk for $3.
because 1 gallon is 4 quarts and she will only buy 2 quarts for the same price.
Hope this helps :)
The answer is A because we simplify the 7 b by subtracting 6 b which gives us 1 b but in this case it will just be B and then we add 7c
Answer:
a) There is outlier (lower category), but this outlier seem certain to be due to an error.
b) There is outlier (upper category), this outlier seem certain to be conceivably correct.
Step-by-step explanation:
a) The outlier in the rock weight is certain to be due to an error. As shown, the rock was weighed five time to ascertain the actual weight or perhaps to known the mean weight. <em>Thus, having a value 4.91 can not be true. It can only be due to an error of recording the values.</em> It suppose to be recorded as 49.1.
b) Since this was a sample of annual income of five different families, it quite possible that a particular family annual income is $1, 200, 000. Hence, we cannot regard this outlier an error, rather conceivably true.
See attached for the box plot of the two data sets.
Problem: find 0 ≤ x ≤ 28 such that x^85 ≡ 6 modulo 35.
By Fermat-Euler theorem:
If a and n are coprime, i.e. (a,n)=1, then
a^phi(n) ≡ 1 mod n
where phi(n)=totient function, the number of positive integers less than n that is coprime with n.
for n=35, phi(35)=24 calculated as follows:
There are 10 positive integers from 1 to 34 which are NOT coprime with 35, namely {5,7,10,14,15,20,21,25,28,30}.Therefore phi(35)=34-10=24
From Fermat-Euler theorem,
x^(phi(35) = x^24 ≡ 1 modulo 35 since (24,35)=1, i.e. 24 and 35 are coprime.
=>
x^12 ≡ ± 1 modulo 35. ...........(1)
and
x^85 ≡ x^(85-3*24) ≡ x^(85-72) ≡ x^(13) ≡ 6 mod 35 ............(2)
Substituting (1) in (2)
x^(12)*x ≡ 6 mod 35
=>
(+1)*x = 6 mod 35 or (-1)*x ≡ 6 mod 35
x ≡ 6 mod 35 x ≡ -6 mod 35 (rejected)
=> x=6
So
6^85 ≡ 6 mod 35
If any clarifications are needed or if you find any errors, please post.
Answer:
i think you got that right its negative
Step-by-step explanation:
