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2 years ago

7

Graph the line represented by x = -3

1 answer:

olganol [36]2 years ago

8 0

It's going to be graphed at coordinate (0,-3)

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Evaluate the following expression. Round your answer two decimal places. Log3(10)

Elanso [62]

$\bf \textit{Logarithm Change of Base Rule}
\\\\
log_a b\implies \cfrac{log_c b}{log_c a}\\\\
-------------------------------\\\\
log_3(10)\implies \cfrac{log_{10}(10)}{log_{10}(3)}\implies \cfrac{1}{log(3)}$

and you can just plug that in your calculator.

3 0

3 years ago

Read 2 more answers

Need help please its my last question

Nesterboy [21]

Given:

Radius of circle = 12 units

Area of sector = 24π sq. units.

Central angle = x

To find:

The value of x.

Solution:

We have,

$r=12$

$A=24\pi$

$\theta = x$

We know that, area of a sector is

$A=\dfrac{\theta }{360^\circ}\pi r^2$

Where, $\theta$ is central angle, r is radius.

$24\pi=\dfrac{x}{360^\circ}\pi (12)^2$

$24\pi=\dfrac{x}{360^\circ}\pi (144)$

$\dfrac{24\pi}{144\pi}=\dfrac{x}{360^\circ}$

$\dfrac{1}{6}=\dfrac{x}{360^\circ}$

Multiply both sides by 360 degrees.

$\dfrac{1}{6}\times 360^\circ=x$

$60^\circ=x$

The value of x is 60 degrees.

Therefore, the correct option is A.

4 0

3 years ago

Match each proportion to its solution.

Aleksandr-060686 [28]

Answer:

x/10=-30/100 : -3

5/35 = 1/a : 7

2/x = 100/15 : .3

12/k = 4/1 : 3

2/8 = g/4 : 1

Step-by-step explanation:

5 0

2 years ago

You invest $2000 in an account that pays 2.7% interest compunded annually. If you make no payments into the account, what will t

vaieri [72.5K]

Answer:

Annually: 2,610.56

Monthly: 2,619.13

Step-by-step explanation:

3 0

2 years ago

Which statements are true about David's work? Check all that apply. The GCF of the coefficients is correct. The GCF of the varia

Anon25 [30]

Answer:

The GCF of the coefficients is correct.

The variable c is not common to all terms, so a power of c should not have been factored out.

In step 6, David applied the distributive property.

Step-by-step explanation:

Given the polynomial :

80b⁴ – 32b²c³ + 48b⁴c

The Greatest Common Factor (GCF) of the coefficients:

80, 32, 48

Factors of :

80 : 1, 2, 4, 5, 8, 10, 16, 20, 40, and 80

32 : 1, 2, 4, 8, 16, and 32

48 : 1, 2, 3, 4, 6, 8, 12, 16, 24, and 48.

GCF = 16

b⁴, b², b⁴

b⁴ = b * b * b * b

b² = b * b

b⁴ = b * b * b * b

GCF = b*b = b²

GCF of c³ and c

c³ = c * c * c

c = c

GCF = c

We can see that David's GCF of the coefficients are all correct

From the polynomial ; 80b⁴ does not contain c ; so factoring out c is incorrect

In step 6 ; the distributive property was used to obtain ; 16b²c(5b² – 2c² + 3b²)

6 0

2 years ago

Read 2 more answers