Answer:
multiply all the numbers
Step-by-step explanation:
Find the smallest number that is divisible by 2, 3, 4, 5, 6 and add 1.
We need the least common multiple of 2, 3, 4, 5, 6.
2 = 2
3 = 3
4 = 2^2
5 = 5
6 = 2 * 3
LCM = product of common and not common prime factors with larger exponent.
LCM = 2^2 * 3 * 5 = 4 * 3 * 5 = 60
To always have a remainder of 1, you need of add 1 to 60.
The number is 61.
Check:
61/2 = 30 remainder 1
61/3 = 20 remainder 1
61/4 = 15 remainder 1
61/5 = 12 remainder 1
61/6 = 10 remainder 1
1.527 is that one of the options?
Answer: https://mathantics.com/
Step-by-step explanation: use that I hope it helps
Answer:
x=3 is one solution
3=3 has infinitely solutions
6=3 has one solutions.
Step-by-step explanation:
I got it correct on Edg.
