Answer:
The volume of the concentrated 80 gallons mixture is 20 gallons
The volume of water in the 80 gallons mixture is 60 gallons
Step-by-step explanation:
The given parameters are;
The content of Container A = The cleaner
The concentration of the cleaner = 20% solution
The content of Container B = Pure water
The concentration of the desired solution = 5%
The volume of the required solution = 80 gallons
Let x represent the volume of the concentrated solution and y represent the volume of water in the 80 gallons mixture
Therefore, we have;
20/100 × x + y×0 = 5/100×80
x + y = 80
y = 80 - x
20/100 × x + (80 - x)×0 = 5/100×80
0.2·x = 4
x = 4/0.2 = 20
x = 20 gallons
y = 80 - x = 80 - 20 = 60
y = 60 gallons
The volume of the concentrated solution (80 gallons mixture) = x = 20 gallons
The volume of water in the 80 gallons mixture = y = 60 gallons.
Steps to solve:
3x + 2 = 8
~Subtract 2 to both sides
3x = 6
~Divide 3 to both sides
x = 2
Best of Luck!
Answer:
1)· 5x + 2y = 9. First we solve for y. 2y= 9 -5x. y=(9-5x)/2. Now that we have the value of y. We substitute on the original equation and resolve. 5x + 2y = 95x + 2y = 9 5x + 2(9-5x)/2 = 9 5x + 9 - 5x = 9 9 = 9
That would be x = 1
Now substitute and resolve to find y.
5(1) + 2y = 9
5 + 2y = 9
2y = 4
y = 2
So our answer x=1 and y = 2. (1,2)
Proof :
5(1) + 2(2) = 9
5+ 4 = 9
9 = 9
Step-by-step explanation:
hoped it helped for the first one i didnt now the second one
Answer:
2x + 1 ≥ 11
Step-by-step explanation:
I believe this is it. Hope this helped!
