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2 years ago

12

Principal $2000 rate of interest 4% time 3 years

1 answer:

fomenos2 years ago

4 0

Answer:

principal =2000

rate of interest=4%

time=3 years

now,

P×T×R÷100

2000×4×3÷100

24000÷100

240....

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If 12000 people voted in the election,how many people were from 50 to 64 years old

inessss [21]

Assuming that this question is based on a graph, and that this graph tells us that people 50-64 years make up 35% of all the voters, then it would mean that
35%of 12000= $\frac{35}{100} *12000=35*120=4200$

So, assuming that people at age 50-64 make up 35% of the voters, then 4200 of them voted.

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3 years ago

If the point is reflected across the x-axis, what is the location of the new point?

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2 years ago

Read 2 more answers

If f(2) =20 and f(3) =10<br>F(4) = ,f(5)=

Arada [10]

F(4)=0 and F(5)= -10

5 0

2 years ago

Can anyone help me with these questions plz

KonstantinChe [14]

Answers:

7: 20 miles

8: 28 miles

9: 1 error

10: Their speed is 50

11: 365 words in 5 mins

Step-by-step explanation:

#7 and #8

Our equation is: $f=2.25+0.20(m-1)$ With f meaning "fare" (price) and m meaning "miles".

Question 7 - Juan's fare for his ride costs $6.05. We must solve for $m$ .

Step 1. Substitute - <em>Substitute the fare for $f$ in the equation.</em>

$6.05=2.25+0.20(m-1)$

Step 2. Simplify/Solve - Solve for $m$ .

$6.05=2.25+0.20(m-1)$

<em>- Distribute</em>

$6.05=2.25+0.2m-0.2$

<em>- Subtract 0.2 from 2.25</em>

$6.05=2.05+0.2m$

<em>- Subtract -2.05 from 6.05</em>

$4=0.2m$

<em>- Divide both sides by 0.2</em>

$20=m$

<u>And you have your answer of 20 miles.</u>

Question 8 - Same equation, different fare.

Step 1. Substitute

$7.65=2.25+0.20(m-1)$

Step 2. Solve

$7.65=2.25+0.20(m-1)\\7.65=2.25+0.20m-0.20\\7.65=2.05+0.20m\\5.6=0.20m\\28=m$

And like so, we have $m = 28$

Questions 9 - 11

<em>The equation given is $S=\frac{1}{5} (w-10e)$ . S = typing speed, w = words per 5 mins, and e= errors.</em>

Question 9 -

<em>We are given this information: S = 55, W = 285. We are solving for e</em>.

Substitute -

$55=\frac{1}{5} (285 -10e)$

Solve -

$55=\frac{1}{5} (285 -10e)\\55=\frac{1}{5} (285 -10e)\\55= 57-2e\\-2=-2e\\1=e$

So they would make 1 error.

Question 10 -

<em>Information given: 300 = w, 5=e. We are solving for S</em>

Substitute -

$S= \frac{1}{5} (300-10(5))$

Solve -

$S= \frac{1}{5} (300-10(5))\\S= \frac{1}{5} (300-50)\\S= \frac{1}{5} (300-50)\\S= \frac{1}{5} (250)\\S= 50$

Their speed is 50.

Question 11 -

<em>Information given: S = 65, e = 4. We are solving for w.</em>

Substitute -

$65=\frac{1}{5} (w-10(4))$

Solve -

$65=\frac{1}{5} (w-10(4))\\65=\frac{1}{5} (w-40)\\65=\frac{1}{5}w-8\\73=\frac{1}{5}w\\365=w$

So w = 365.

Hoped this helped!~

7 0

3 years ago

Add. Write your answer using rectangular coordinates. -3∠-30° + 9∠32°

sukhopar [10]

(-3*cos30,-3*sin30)+(9*cos32,9*sin32)

but we don't have sin,cos32. are you sure it's 32? or 30?

4 0

2 years ago