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Degger [83]
4 years ago
8

How many three-digit numbers greater than 200 can be formed from the digits 1, 2, 6, 7, and 9, if the digits can be repeated?

Mathematics
1 answer:
const2013 [10]4 years ago
6 0
269,296,267,297,279,216,261,217,271,219,291,612,621,617,671,691,619
THERE IS MANY WAYS YOU CAN DO IT! I would right it all down then count it, or go with 100

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If f(x) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B9%7D" id="TexFormula1" title="\frac{1}{9}" alt="\frac{1}{9}" align=
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Answer:

Solution given:

f(x) = \frac{1}{9} x-2

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So

<u>F</u><u>-</u><u>¹</u><u>(</u><u>x</u><u>)</u><u>=</u><u>9</u><u>x</u><u>+</u><u>1</u><u>8</u>

<u>a</u><u>n</u><u>d</u>

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